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Q7.6:
What is meant by hydroboration-oxidation reaction? Illustrate it with an example.

Solution :

1. Theoretical Foundation of Hydroboration-Oxidation

Hydroboration-oxidation is a two-step organic chemical reaction that converts an alkene into an alcohol. The reaction is characterized by its anti-Markovnikov regioselectivity and syn-stereospecificity [Per the mechanism of electrophilic addition of boron hydrides].

2. Stepwise Reaction Mechanism

Step A: Hydroboration
An alkene reacts with diborane ($B_2H_6$) or its complex (usually $BH_3 \cdot THF$) to form an organoborane intermediate. The boron atom, being electrophilic, adds to the less hindered carbon atom of the double bond [Per the Steric Hindrance Effect].

$3R-CH=CH_2 + \frac{1}{2}B_2H_6 \rightarrow (R-CH_2-CH_2)_3B$

Step B: Oxidation
The trialkylborane intermediate is treated with hydrogen peroxide ($H_2O_2$) in the presence of an aqueous base ($OH^-$). This replaces the boron atom with a hydroxyl ($-OH$) group with retention of configuration.

$(R-CH_2-CH_2)_3B + 3H_2O_2 + OH^- \rightarrow 3R-CH_2-CH_2OH + B(OH)_4^-$

3. Illustrative Example: Propene to Propan-1-ol

The conversion of propene ($CH_3-CH=CH_2$) demonstrates the anti-Markovnikov nature of the reaction, yielding the primary alcohol as the major product.

Propene: CH₃-CH=CH₂ 1. BH₃ / THF 2. H₂O₂, OH⁻ Propan-1-ol: CH₃-CH₂-CH₂OH

4. Comparative Summary

Feature Description
Regiochemistry Anti-Markovnikov (OH attaches to the carbon with more hydrogens).
Stereochemistry Syn-addition (H and OH add to the same face of the alkene).
Reagent Diborane ($B_2H_6$) followed by alkaline $H_2O_2$.

Final Solution: The hydroboration-oxidation reaction is an anti-Markovnikov hydration process where an alkene is treated with borane followed by oxidation with hydrogen peroxide to yield a primary alcohol, as seen in the conversion of propene to propan-1-ol ($CH_3CH_2CH_2OH$).


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