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Q7.1(xii):

Write IUPAC names of the following compounds:

Solution :

Step 1: Structural Analysis and Identification of Functional Groups

The provided chemical structure is: $CH_3-CH(Cl)-CH_2-CH(OH)-CH_3$.

The molecular framework consists of a five-carbon parent chain (pentane derivative) containing two primary functional groups: a chloro- group ($-Cl$) and a hydroxyl group ($-OH$). [Per IUPAC Nomenclature Rules for polyfunctional compounds].

Step 2: Selection of the Parent Carbon Chain

The longest continuous carbon chain containing the principal functional group ($-OH$) consists of 5 carbon atoms. Therefore, the parent alkane is pentane. [Per IUPAC Rule: The suffix for an alcohol is '-ol', which takes precedence over halogen substituents].

Step 3: Numbering the Carbon Chain

Numbering must be done such that the principal functional group ($-OH$) receives the lowest possible locant. [Per IUPAC Rule: Principal functional groups have priority in numbering].

Carbon Position 1 2 3 4 5
Substituent/Group $CH_3$ $CH(OH)$ $CH_2$ $CH(Cl)$ $CH_3$

Numbering from right to left: $C_1(H_3)-C_2(H)(OH)-C_3(H_2)-C_4(H)(Cl)-C_5(H_3)$.

In this numbering scheme:

  • The $-OH$ group is at position 2.
  • The $-Cl$ group is at position 4.

Step 4: Compiling the IUPAC Name

Substituents are listed in alphabetical order. 'Chloro' comes before the base name. [Per IUPAC Rule: Alphabetical ordering of prefixes].

  • Chloro substituent: 4-chloro
  • Parent chain: pentan
  • Hydroxyl position: -2-ol

Visual Representation of Molecule

CH3 CH-Cl CH2 CH-OH CH3

Conclusion

Combining the components 4-chloro (substituent) + pentan (parent) + 2-ol (functional group), the nomenclature is established.

Final Solution: 4-chloropentan-2-ol


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