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Q7.1:

Write IUPAC names of the following compounds:

Solution :

Step 1: Structural Analysis of the Compound

The provided chemical structure is a branched aliphatic alcohol. By analyzing the carbon skeleton, we identify the longest continuous carbon chain containing the principal functional group ($-OH$):

Structure: $CH_3-CH_2-CH(CH_3)-CH(OH)-CH_2-CH_3$

The carbon chain consists of 6 carbon atoms, making it a derivative of hexane [Per IUPAC nomenclature rules for alkanes].

Step 2: Determining Numbering and Substituents

To assign the lowest locants to the substituents and the principal functional group:

  • Numbering from left to right: The $-OH$ group is at $C_3$, and the $-CH_3$ (methyl) group is at $C_4$.
  • Numbering from right to left: The $-OH$ group is at $C_4$, and the $-CH_3$ (methyl) group is at $C_3$.

[By the IUPAC Rule of Lowest Locants, the principal functional group $-OH$ must receive the lowest possible number.] Therefore, we must number the chain from left to right, assigning $C_3$ to the hydroxyl group.

Step 3: Compiling the Systematic Name

Based on the selected numbering:

Component Description
Parent Chain Hexane ($6$ carbons)
Principal Functional Group $-ol$ at position $3$
Substituent $4-methyl$

Combining these elements alphabetically and numerically: $4-methyl$ + $hexan$ + $3-ol$.

Step 4: Molecular Visualization

$C_1$ $C_2$ $C_3$ $C_4$ $C_5$ $C_6$ $-OH$ $-CH_3$

Final Solution: The IUPAC name of the compound is 4-methylhexan-3-ol.


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