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Q7.13(iii):
Show how will you synthesise: pentan-1-ol using a suitable alkyl halide?

Solution :

Step 1: Identification of Reactants and Target Molecule

The objective is to synthesize pentan-1-ol ($CH_3CH_2CH_2CH_2CH_2OH$), which is a primary alcohol containing five carbon atoms, from a suitable alkyl halide. To introduce a hydroxyl ($-OH$) group into an alkyl halide chain, the standard reaction is the nucleophilic substitution of a halogen atom with a hydroxide ion ($OH^-$).

Step 2: Selection of Alkyl Halide

To obtain pentan-1-ol, we require a five-carbon alkyl halide, 1-chloropentane ($CH_3CH_2CH_2CH_2CH_2Cl$) or 1-bromopentane ($CH_3CH_2CH_2CH_2CH_2Br$). 1-Bromopentane is preferred due to the superior leaving group ability of the bromide ion compared to the chloride ion [Per the nucleophilic substitution kinetics, $S_N2$ reactivity order $I > Br > Cl > F$].

Step 3: Reaction Mechanism and Conditions

The transformation involves an $S_N2$ nucleophilic substitution mechanism. The primary alkyl halide reacts with an aqueous solution of a strong base, such as sodium hydroxide ($NaOH$) or potassium hydroxide ($KOH$).

Chemical Equation:

$CH_3CH_2CH_2CH_2CH_2Br + KOH_{(aq)} \xrightarrow{\Delta} CH_3CH_2CH_2CH_2CH_2OH + KBr$

Step 4: Visualizing the SN2 Transition State

Nucleophilic Attack by OH⁻ on 1-Bromopentane HO⁻ C₅H₁₁ Br⁻ Transition State (Sₙ2)

Step 5: Analytical Summary of the Transformation

Reagent Type Function
1-Bromopentane Alkyl Halide Electrophilic substrate
Aqueous $KOH/NaOH$ Nucleophile Replaces Halogen via $S_N2$ pathway

The use of an aqueous medium is critical. If an alcoholic (ethanolic) solution were used, the reaction would favor an elimination mechanism (dehydrohalogenation) [Per Zaitsev's Rule], producing pent-1-ene instead of the desired alcohol. Therefore, strictly aqueous conditions must be maintained to ensure the hydroxide ion functions as a nucleophile rather than a base.

Final Solution: Pentan-1-ol is synthesized by the nucleophilic substitution of 1-bromopentane with aqueous potassium hydroxide: $CH_3CH_2CH_2CH_2CH_2Br + KOH_{(aq)} \rightarrow CH_3CH_2CH_2CH_2CH_2OH + KBr$.


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