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Q7.26:
How is 1-propoxypropane synthesised from propan-1-ol? Write mechanism of this reaction.

Solution :

Reaction Setup: Dehydration of Propan-1-ol

The synthesis of 1-propoxypropane (an asymmetrical or symmetrical ether) from propan-1-ol ($CH_3CH_2CH_2OH$) is achieved via the intermolecular acid-catalyzed dehydration of the alcohol. This reaction occurs at a lower temperature ($413 \, K$) compared to the formation of alkenes ($443 \, K$).

The balanced chemical equation is:

$2 CH_3CH_2CH_2OH \xrightarrow{H_2SO_4, 413 K} CH_3CH_2CH_2-O-CH_2CH_2CH_3 + H_2O$

Reaction Mechanism: $S_N2$ Pathway

The mechanism proceeds via a nucleophilic substitution ($S_N2$) pathway. Since the substrate is a primary alcohol, the mechanism involves the following three discrete stages:

Step 1: Protonation of the Alcohol

The oxygen atom of the propan-1-ol molecule possesses two lone pairs, which act as a Lewis base. It attacks the proton ($H^+$) provided by the acid catalyst (e.g., $H_2SO_4$) to form an alkyloxonium ion [Per Brønsted-Lowry acid-base theory].

$CH_3CH_2CH_2\ddot{O}H + H^+ \rightleftharpoons CH_3CH_2CH_2\overset{+}{O}H_2$

Step 2: Nucleophilic Attack ($S_N2$)

A second molecule of non-protonated propan-1-ol acts as a nucleophile. The lone pair on the oxygen of this molecule attacks the $\alpha$-carbon of the protonated alcohol. Simultaneously, the $C-O$ bond breaks to release a water molecule [By $S_N2$ kinetics, the rate is proportional to the concentration of both species].

$CH_3CH_2CH_2\ddot{O}H + CH_3CH_2CH_2\overset{+}{O}H_2 \rightarrow [CH_3CH_2CH_2-O^+(H)-CH_2CH_2CH_3] + H_2O$

Step 3: Deprotonation

The resulting intermediate is a protonated ether. It loses a proton to the surrounding medium to regenerate the acid catalyst and form the final ether, 1-propoxypropane.

$CH_3CH_2CH_2-\overset{+}{O}(H)-CH_2CH_2CH_3 \rightarrow CH_3CH_2CH_2-O-CH_2CH_2CH_3 + H^+$

Visual Representation of Mechanism

Step 1: R-OH + H+ → R-OH2+ Step 2: R-OH + R-OH2+ → R-O+(H)-R + H2O Step 3: R-O+(H)-R → R-O-R + H+ R = CH3CH2CH2-

Conditions for Success:

  • Temperature Control: Must be maintained at approximately $413 \, K$. Excess heat leads to elimination (dehydration to propene).
  • Substrate Type: This method is highly efficient for primary alcohols. Secondary and tertiary alcohols primarily yield alkenes due to steric hindrance and the stability of the carbocation intermediate.

Final Solution: 1-propoxypropane is synthesized via the acid-catalyzed intermolecular dehydration of propan-1-ol at 413 K, following an $S_N2$ reaction mechanism.


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