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Q7.26:
How is 1-propoxypropane synthesised from propan-1-ol? Write mechanism of this reaction.

Solution :

Step 1: Chemical Reaction Scheme

The synthesis of 1-propoxypropane (an unsymmetrical/symmetrical ether) from propan-1-ol is achieved via the acid-catalyzed intermolecular dehydration of alcohols. This is a nucleophilic substitution reaction ($S_N2$).

Reaction: $2CH_3CH_2CH_2OH \xrightarrow{H_2SO_4, 413 K} CH_3CH_2CH_2-O-CH_2CH_2CH_3 + H_2O$

Step 2: Reaction Mechanism

The mechanism follows three distinct stages [Per the mechanism of acid-catalyzed dehydration of primary alcohols]:

  • Stage 1: Protonation of Propan-1-ol
    The oxygen atom of the alcohol is protonated by the acid catalyst to form an alkyloxonium ion, making the carbon atom more electrophilic and the hydroxyl group a better leaving group.
    $CH_3CH_2CH_2-OH + H^+ \rightleftharpoons CH_3CH_2CH_2-O^+H_2$
  • Stage 2: Nucleophilic Attack ($S_N2$)
    A second molecule of propan-1-ol acts as a nucleophile, attacking the protonated alcohol molecule at the electrophilic $\alpha$-carbon, displacing a water molecule.
    $CH_3CH_2CH_2-OH + CH_3CH_2CH_2-O^+H_2 \rightarrow CH_3CH_2CH_2-O^+(H)-CH_2CH_2CH_3 + H_2O$
  • Stage 3: Deprotonation
    The intermediate protonated ether is deprotonated by the solvent or another alcohol molecule to yield the final ether product and regenerate the acid catalyst.
    $CH_3CH_2CH_2-O^+(H)-CH_2CH_2CH_3 \rightarrow CH_3CH_2CH_2-O-CH_2CH_2CH_3 + H^+$

Step 3: Visual Representation of the Mechanism

R-OH + H⁺ → R-OH₂⁺ R-OH + R-OH₂⁺ → R-O⁺(H)-R + H₂O R-O⁺(H)-R → R-O-R + H⁺ Where R = CH₃CH₂CH₂-

Step 4: Critical Conditions

This reaction requires a specific temperature control ($413 K$):

  • At $413 K$, the primary mechanism is substitution ($S_N2$), favoring ether formation.
  • If the temperature exceeds $443 K$ (e.g., $443 K$ with conc. $H_2SO_4$), the mechanism shifts to an $E2$ elimination, favoring the formation of propene as the major product [Per Zaitsev's Rule application in dehydration].

Final Solution: 1-Propoxypropane is synthesized by heating propan-1-ol with concentrated sulfuric acid at 413 K via an $S_N2$ mechanism involving the protonation of the alcohol followed by nucleophilic attack of a second alcohol molecule and subsequent deprotonation.


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