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Sandhya replied | 2 days ago

The IIT JAM Mathematics syllabus includes Real Analysis, Multivariable Calculus, Differential Equations, Linear Algebra, and Algebra. Key topics within these sections are sequences and series, limits, continuity, differentiation, integration, matrices, vector spaces, eigenvalues, eigenvectors, and group theory. 

Sandhya replied | 2 days ago

To prepare for the IIT JAM Economics exam, first, thoroughly understand the syllabus focusing on Microeconomics, Macroeconomics, Mathematical Economics, and Statistics. Create a detailed study plan and focus on conceptual clarity rather than rote memorization. Practice a high volume of numerical problems and solve previous years' question papers and mock tests to get familiar with the exam pattern, time management, and your weak areas. 

Suraj replied | 2 days ago

It translates to "Katha" which means "Story" and "Kali" meaning "Play" in Malayalam. It means to tell stories(Hindu mythological) using bodily/facial expressions and is performed at dedicated sanctums primarily.

Suraj replied | 2 days ago

"Kathakali" is traditional art form from Kerala. Basically it is done to convey the "epics" (stories) to the audience via facial expressions and bodily gestures, topped with special makeups/outfits/traditional music(story/singing is done by dedicated members and Kathakali artist is not allowed to speak but to express). It's generally perfomed in Temple/associated cultural places and the stories are typically extracts from Hindu mythology.

Sumaiya replied | 2 days ago

Given:

• Area of head = 15 cm × 15 cm

• So, $A = 15 × 15 = 225 \text{ cm}^2$A=15×15=225 cm2

Now we need to find the weight of air above this area — that means we must consider air pressure.

Step 1: Standard atmospheric pressure

At sea level,

$$1 \text{ atmosphere} = 1.013 \times 10^5 \text{ N/m}^2$$1 atmosphere=1.013×105 N/m2

Step 2: Convert area from cm² to m²

$$225 \text{ cm}^2 = 225 × 10^{-4} \text{ m}^2 = 0.0225 \text{ m}^2$$225 cm2=225×10−4 m2=0.0225 m2

Step 3: Force on the head due to air pressure

$$\text{Force} = \text{Pressure} × \text{Area}$$Force=Pressure×Area $$F = 1.013 × 10^5 × 0.0225 = 2280 \text{ N (approximately)}$$F=1.013×105×0.0225=2280 N (approximately)

Step 4: Convert force to equivalent weight (mass)

$$\text{Weight} = mg \implies m = \frac{F}{g}$$Weight=mg⟹m=gF

Using $g = 9.8 \text{ m/s}^2$g=9.8 m/s2:

$$m = \frac{2280}{9.8} ≈ 232.65 \text{ kg}$$m=9.82280≈232.65 kg

✅ Final Answer:
You are carrying approximately 230 kilograms of air on your head due to atmospheric pressure!