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Q7.12:
You are given benzene, conc. \(H_{2}SO_{4}\) and \(NaOH\). Write the equations for the preparation of phenol using these reagents.

Solution :

Step 1: Sulfonation of Benzene

The first step involves the electrophilic aromatic substitution of benzene with concentrated sulfuric acid ($H_{2}SO_{4}$) to produce benzenesulfonic acid. Heating benzene with fuming sulfuric acid (oleum) or concentrated $H_{2}SO_{4}$ facilitates this process.

Equation: $C_{6}H_{6} + H_{2}SO_{4} \xrightarrow{\Delta} C_{6}H_{5}SO_{3}H + H_{2}O$
[Justification: Electrophilic aromatic substitution mechanism where $SO_{3}$ acts as the electrophile].

Step 2: Formation of Sodium Benzenesulfonate

The benzenesulfonic acid produced is treated with sodium hydroxide ($NaOH$) to neutralize the sulfonic acid group, forming the sodium salt, sodium benzenesulfonate.

Equation: $C_{6}H_{5}SO_{3}H + NaOH \rightarrow C_{6}H_{5}SO_{3}Na + H_{2}O$
[Justification: Acid-base neutralization reaction].

Step 3: Alkali Fusion

Sodium benzenesulfonate is fused with excess molten sodium hydroxide ($NaOH$) at a high temperature (approximately 573-623 K). This step yields sodium phenoxide.

Equation: $C_{6}H_{5}SO_{3}Na + 2NaOH \xrightarrow{573-623 K} C_{6}H_{5}ONa + Na_{2}SO_{3} + H_{2}O$
[Justification: Nucleophilic aromatic substitution].

Step 4: Acidification to Yield Phenol

Finally, the sodium phenoxide salt is treated with a dilute mineral acid (such as $HCl$ or $H_{2}SO_{4}$) to obtain phenol.

Equation: $C_{6}H_{5}ONa + HCl \rightarrow C_{6}H_{5}OH + NaCl$
[Justification: Acid-base protonation of the phenoxide ion].

Benzene conc. H2SO4 C6H5SO3H NaOH C6H5ONa H+ Phenol (C6H5OH)

Final Solution: The preparation of phenol from benzene proceeds via sulfonation to benzenesulfonic acid, followed by reaction with NaOH to form sodium benzenesulfonate, fusion to sodium phenoxide, and final acidification to produce phenol ($C_{6}H_{5}OH$).


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