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Q7.32(ii):

Show how would you synthesise the following alcohols from appropriate alkenes?

 

Solution :

Given Variables & Initial Setup

The target molecule is 1-methylcyclohexanol. To synthesize this from an appropriate alkene via acid-catalyzed hydration, we must identify the starting alkene that obeys Markovnikov's rule.

Target Molecule: $1\text{-methylcyclohexan-1-ol}$

Starting Material: 1-methylcyclohexene

Step 1: Chemical Equation Formulation

The synthesis involves the electrophilic addition of water ($H_2O$) to $1\text{-methylcyclohexene}$ in the presence of an acid catalyst ($H^+$), typically $H_2SO_4$.

Chemical Reaction: $\text{C}_7\text{H}_{12} + \text{H}_2\text{O} \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_7\text{H}_{14}\text{O}$

Step 2: Reaction Mechanism Analysis

1. Protonation: The double bond of $1\text{-methylcyclohexene}$ acts as a nucleophile, attacking the hydronium ion ($H_3O^+$). [Per Markovnikov's rule, the proton adds to the less substituted carbon to generate the most stable carbocation].

2. Carbocation Formation: A tertiary ($3^{\circ}$) carbocation is formed at the $C1$ position, which is more stable than a secondary carbocation. [By Stability of Carbocations: $3^{\circ} > 2^{\circ} > 1^{\circ}$].

3. Nucleophilic Attack: Water molecules act as a nucleophile and attack the tertiary carbocation at $C1$.

4. Deprotonation: A base (water) removes a proton to yield the final alcohol product and regenerate the acid catalyst.

Visual Representation of Reaction

1-methylcyclohexene H2O / H+ 1-methylcyclohexanol OH CH3 CH3

Data Summary Table

Reagent Role Function
$1\text{-methylcyclohexene}$ Substrate Provides the alkene double bond
$H_2O$ Nucleophile Provides the $-OH$ group
$H_2SO_4$ Catalyst Provides $H^+$ to initiate carbocation formation

Final Solution: The synthesis of 1-methylcyclohexanol is achieved by the acid-catalyzed hydration of 1-methylcyclohexene via the formation of a stable tertiary carbocation intermediate.


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