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Q5.7 (vii):
Using IUPAC norms write the systematic names: ([Ni(NH_{3})_{6}]Cl_{2})

Solution :

Step 1: Identification of Coordination Entity and Counter Ions

The chemical formula is $[Ni(NH_{3})_{6}]Cl_{2}$. This compound is a coordination salt consisting of a cationic complex sphere $[Ni(NH_{3})_{6}]^{2+}$ and two anionic counter ions, $Cl^{-}$, termed chloride ions. [Per IUPAC nomenclature rules for coordination compounds, the cation is named before the anion].

Step 2: Determining the Oxidation State of the Central Metal Ion

Let the oxidation state of Nickel ($Ni$) be $x$.

  • The ligand is Ammonia ($NH_{3}$), which is a neutral molecule with an oxidation state of $0$. [Per ligand classification criteria].
  • The chloride ion ($Cl^{-}$) has an oxidation state of $-1$.
  • The sum of oxidation states in a neutral compound must be zero.

Setting up the algebraic equation:

$x + 6(0) + 2(-1) = 0$

$x - 2 = 0 \implies x = +2$

Thus, the oxidation state of Nickel is $II$.

Step 3: Systematic Naming of Ligands and Metal

  • Ligands: The ligand is $NH_{3}$. In IUPAC nomenclature, $NH_{3}$ is named as "ammine". Since there are six such ligands, the prefix "hexa" is used. [Per IUPAC rule for numerical prefixes].
  • Central Metal: Since the complex ion is cationic ($[Ni(NH_{3})_{6}]^{2+}$), the name of the metal remains "Nickel". [Per rules for naming metal centers in complex cations].
  • Oxidation State: The state is indicated by Roman numerals in parentheses immediately following the metal name: $(II)$.

Step 4: Final IUPAC Assembly

Following the standard format: [Prefix + Ligand Name] + [Metal Name (Oxidation State)] + [Counter Ion].

The name is constructed as follows:

Hexa + ammine + nickel(II) + chloride

Combining these, we get: Hexaamminenickel(II) chloride.

Structural Representation of the Complex

Ni NH₃ NH₃ NH₃ NH₃ [Octahedral Geometry]

Final Solution: Hexaamminenickel(II) chloride


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