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Q5.7(iii):
Using IUPAC norms write the systematic names of the following: \([Ti(H_{2}O)_{6}]^{3+}\)

Solution :

Step 1: Identifying the Coordination Entity

The given coordination entity is $[Ti(H_{2}O)_{6}]^{3+}$. This is a cationic complex ion. Per IUPAC nomenclature rules for coordination compounds, cationic complexes are named by listing the ligands first, followed by the central metal atom/ion, and ending with its oxidation state in Roman numerals enclosed in parentheses [Per IUPAC Red Book, Rule IR-9.2.3].

Step 2: Analyzing Ligands and Central Metal Atom

  • Ligand: The species $H_{2}O$ is a neutral ligand known as 'aqua' [Per IUPAC Table IV].
  • Ligand Count: There are $6$ molecules of water, denoted by the numerical prefix 'hexa-'.
  • Central Metal: The central metal is Titanium ($Ti$). Since the complex is a cation, the name of the metal remains 'Titanium' (unlike anionic complexes where the suffix '-ate' would be appended) [Per IUPAC Rule IR-9.2.3.2].

Step 3: Calculating Oxidation State of Titanium

Let the oxidation state of Titanium be $x$.

  • Oxidation state of neutral ligand $H_{2}O = 0$.
  • The total charge on the complex ion is $+3$.

Setting up the algebraic equation:

$x + 6(0) = +3$

$x = +3$

[By the Principle of Electroneutrality in Coordination Chemistry]

Step 4: Constructing the IUPAC Name

Synthesizing the components: (Prefix) + (Ligand Name) + (Metal Name) + (Oxidation State).

Result: hexa + aqua + titanium + (III)

Note: Since the chemical species is an ion, the word "ion" must be appended to the final string [Per IUPAC Rule IR-9.2.3.3].

Visual Representation of the Octahedral Geometry

Ti³⁺ H₂O H₂O H₂O H₂O H₂O H₂O

Final Solution: Hexaaquatitanium(III) ion


More Questions from Class 12 Chemistry Coordination Compounds Exercises


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