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Q5.11 (ii):
Draw all the isomers (geometrical and optical) of: ([Co(NH_{3})Cl(en)_{2}]^{2+})

Solution :

Step 1: Analyzing the Coordination Entity

The complex ion is $[Co(NH_{3})Cl(en)_{2}]^{2+}$.

  • Central Metal: Cobalt ($Co^{3+}$), which is $d^6$ in an octahedral geometry.
  • Ligands: One $NH_{3}$ (monodentate), one $Cl^{-}$ (monodentate), and two $en$ (ethylenediamine, bidentate).
  • Coordination Number (CN): $1 + 1 + (2 \times 2) = 6$. The geometry is octahedral.

Step 2: Determining Geometrical Isomers

Since there are two bidentate ligands ($en$) and two distinct monodentate ligands ($NH_{3}$ and $Cl^{-}$), we focus on the relative orientation of the monodentate ligands.

  • cis-Isomer: The $NH_{3}$ and $Cl^{-}$ are adjacent ($90^{\circ}$ angle).
  • trans-Isomer: The $NH_{3}$ and $Cl^{-}$ are opposite ($180^{\circ}$ angle).

Step 3: Evaluating Optical Isomerism

  • cis-[Co(NH_{3})Cl(en)_{2}]^{2+}: This complex lacks a plane of symmetry and a center of inversion. It is chiral and exists as a pair of enantiomers (mirror images).
  • trans-[Co(NH_{3})Cl(en)_{2}]^{2+}: This complex possesses a plane of symmetry (containing the $NH_{3}-Co-Cl$ axis). Therefore, it is achiral and optically inactive.

Step 4: Visualizing the Isomers

NH₃ Cl⁻ Co³⁺ Cis-isomer (Chiral) NH₃ Cl⁻ Co³⁺ Trans-isomer (Achiral)

Step 5: Tabular Summary of Isomeric Forms

Isomer Geometrical Orientation Optical Activity
Cis-isomer $NH_{3}$ and $Cl^{-}$ are cis Optically Active (2 Enantiomers)
Trans-isomer $NH_{3}$ and $Cl^{-}$ are trans Optically Inactive

Final Solution: The complex $[Co(NH_{3})Cl(en)_{2}]^{2+}$ exhibits two geometrical isomers: the cis-isomer (which is optically active and exists as a pair of d- and l-enantiomers) and the trans-isomer (which is optically inactive). Total number of isomers = 3.


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