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Q8.5(ii):
Draw structures of the following derivative. (ii) Cyclopropanone oxime

Solution :

Step 1: Structural Analysis of the Parent Molecule

To determine the structure of cyclopropanone oxime, we must first analyze the parent carbonyl compound, cyclopropanone ($C_3H_4O$).

  • The parent molecule contains a three-membered carbon ring (cyclopropane).
  • The carbonyl functional group ($C=O$) is located at one of the carbons in the ring.
  • The general structure of cyclopropanone is a triangle of carbon atoms with a double-bonded oxygen atom at one vertex.

Step 2: Derivation of the Oxime Derivative

An oxime is formed via the nucleophilic addition-elimination reaction between a carbonyl compound and hydroxylamine ($NH_2OH$). [Per the mechanism of nucleophilic addition to carbonyl groups].

  1. The carbonyl oxygen ($O$) of the cyclopropanone is replaced by a nitrogen atom double-bonded to the ring carbon ($C=N$).
  2. A hydroxyl group ($-OH$) is attached to the nitrogen atom.
  3. The resulting functional group is the oxime group, expressed as $C=N-OH$.

Step 3: Geometric Representation and Bond Parameters

The cyclopropanone oxime molecule consists of a strained $C_3$ ring. In the oxime derivative, the nitrogen atom is $sp^2$ hybridized, maintaining the $120^\circ$ bond angle requirement at the nitrogen center, while the ring carbons are constrained by the small ring geometry (approx $60^\circ$ internal angles).

C CHâ‚‚ CHâ‚‚ N OH =

Step 4: Summary of Chemical Formula

The chemical formula for cyclopropanone oxime is $C_3H_5NO$. The structural connectivity is defined by the cyclopropane ring bonded to a nitrogen atom, which in turn holds a hydroxyl group, characterized by the partial double bond character between the ring carbon and the nitrogen atom.

Final Solution: The structure of cyclopropanone oxime is a cyclopropane ring where one $CH_2$ group is replaced by a $C=N-OH$ moiety.


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