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Q2.2(c):
Fill in the blanks by suitable conversion of units 3.0 (m s^{-2}) = .... (km h^{-2})

Solution :

Step 1: Establishing the Dimensional Conversion Factors

To convert the unit of acceleration from $\text{m s}^{-2}$ to $\text{km h}^{-2}$, we must independently convert the units of length (meters to kilometers) and the units of time (seconds to hours) within the expression.

  • Conversion of Length: We know that $1 \text{ km} = 10^3 \text{ m}$. Therefore, $1 \text{ m} = 10^{-3} \text{ km}$.
  • Conversion of Time: We know that $1 \text{ hour} = 60 \text{ minutes} = 3600 \text{ seconds}$. Therefore, $1 \text{ s} = \frac{1}{3600} \text{ h}$.

Step 2: Substitution into the Acceleration Expression

The given value is $3.0 \text{ m s}^{-2}$. We substitute the unit equivalents derived in Step 1 into this expression:

$$3.0 \frac{\text{m}}{\text{s}^2} = 3.0 \times \frac{(10^{-3} \text{ km})}{\left(\frac{1}{3600} \text{ h}\right)^2}$$

[By the Principle of Dimensional Homogeneity, units are treated as algebraic quantities.]

Step 3: Algebraic Manipulation and Calculation

Expanding the denominator and simplifying the fractions:

$$3.0 \times 10^{-3} \text{ km} \div \left(\frac{1}{3600^2} \text{ h}^2\right)$$

$$3.0 \times 10^{-3} \times (3600)^2 \text{ km h}^{-2}$$

Calculating the square of $3600$:

$$(3600)^2 = (3.6 \times 10^3)^2 = 12.96 \times 10^6$$

Combining the terms:

$$\text{Value} = 3.0 \times 10^{-3} \times 12.96 \times 10^6$$

$$\text{Value} = 3.0 \times 12.96 \times 10^3$$

$$\text{Value} = 38.88 \times 10^3$$

$$\text{Value} = 38880 \text{ km h}^{-2}$$

Step 4: Significant Figures Adjustment

The initial value $3.0$ contains two significant figures. To maintain precision, we express the result in scientific notation consistent with significant figure conventions:

$$38880 = 3.9 \times 10^4 \text{ km h}^{-2} \text{ (rounded to two significant figures)}$$

3.0 m/s² 38880 km/h² Conversion Path (Factor: 12960)

Final Solution: 3.0 \text{ m s}^{-2} = 3.9 \times 10^4 \text{ km h}^{-2}


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