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Q2.10(f):
State the number of significant figures in the following : (f) 0.0006032 m$^2$

Solution :

Step 1: Establishing the Theoretical Framework

To determine the number of significant figures in a measurement, we must apply the standard conventions established by the International System of Units (SI) and scientific notation protocols [Per the General Conference on Weights and Measures (CGPM) guidelines on significant digits].

Step 2: Analysis of the Numerical String

The given measurement is $0.0006032 \text{ m}^2$. We evaluate the digits based on the following rules:

  • Rule for Leading Zeros: Zeros that appear to the left of the first non-zero digit are considered placeholder zeros used to define the magnitude of the number and are not significant. In the value $0.0006032$, the zeros before the digit '$6$' (specifically the three zeros after the decimal point) serve only as decimal locators.
  • Rule for Non-zero Digits: All non-zero digits are significant. Thus, $6$, $3$, and $2$ are significant.
  • Rule for Interior Zeros: Zeros located between two non-zero digits are significant. The zero between $6$ and $3$ is significant.

Step 3: Logical Breakdown of the Digits

Digit/Sequence Classification Significant?
$0.000$ Leading Zeros No
$6$ Non-zero Digit Yes
$0$ Interior Zero Yes
$3$ Non-zero Digit Yes
$2$ Non-zero Digit Yes

Step 4: Verification via Scientific Notation

To verify the count, convert the measurement into standard scientific notation [Per ISO 80000-1]:

$0.0006032 \text{ m}^2 = 6.032 \times 10^{-4} \text{ m}^2$

In scientific notation ($a \times 10^n$), the number of significant figures is equal to the number of digits in the coefficient ($a$). The coefficient is $6.032$, which contains $4$ digits.

0.000 6 0 3 2 Significant digits (4) Leading zeros (Not significant)

Final Solution: The measurement $0.0006032 \text{ m}^2$ contains 4 significant figures.


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