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Q2.12(b):
The mass of a box measured by a grocer’s balance is 2.30 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is the difference in the masses of the pieces to correct significant figures ?

Solution :

Step 1: Identification of Given Quantities and Units

To perform calculations involving significant figures, all measurements must first be expressed in consistent units. The masses provided are:

  • Mass of gold piece 1 ($m_1$): $20.15 \text{ g}$
  • Mass of gold piece 2 ($m_2$): $20.17 \text{ g}$

[Per the principle of dimensional homogeneity, addition and subtraction operations require identical units. Although the box mass ($2.30 \text{ kg}$) is provided, it is irrelevant to the specific calculation of the difference between the gold pieces.]

Step 2: Calculating the Difference

The difference in mass ($\Delta m$) is calculated as follows:

$\Delta m = m_2 - m_1$

$\Delta m = 20.17 \text{ g} - 20.15 \text{ g}$

$\Delta m = 0.02 \text{ g}$

Step 3: Applying Rules for Significant Figures in Subtraction

According to the arithmetic rules for significant figures in subtraction: "The result of an addition or subtraction should be reported to the same number of decimal places as the measurement with the fewest number of decimal places."

Quantity Value Decimal Places
$m_1$ $20.15 \text{ g}$ 2
$m_2$ $20.17 \text{ g}$ 2

[Justification: Both measurements contain two decimal places. Therefore, the result must be reported to two decimal places.]

Step 4: Vector Representation of Mass Difference

20.15 g 20.17 g Difference = 0.02 g

Step 5: Final Result Formulation

The calculated difference is $0.02 \text{ g}$. Since the measurement $20.15 \text{ g}$ and $20.17 \text{ g}$ are both precise to the hundredths place, the difference $0.02 \text{ g}$ is correctly represented with one significant figure (as leading zeros are not significant), satisfying the precision requirement of the input data.

Final Solution: The difference in the masses of the two gold pieces is 0.02 g.


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