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Q2.18:
Explain this common observation clearly : If you look out of the window of a fast moving train, the nearby trees, houses etc. seem to move rapidly in a direction opposite to the train’s motion, but the distant objects (hill tops, the Moon, the stars etc.) seem to be stationary. (In fact, since you are aware that you are moving, these distant objects seem to move with you).

Solution :

Step 1: Theoretical Foundation of Relative Motion

The observation described is a fundamental application of Relative Velocity. The velocity of an object $B$ relative to object $A$ is defined by the vector equation:
$\vec{v}_{BA} = \vec{v}_B - \vec{v}_A$
where $\vec{v}_B$ is the velocity of the object and $\vec{v}_A$ is the velocity of the observer (the train). [Per Galilean Relativity principles].

Step 2: Analysis of Angular Velocity and Visual Perception

The human perception of motion is fundamentally tied to the angular velocity ($\omega$) of an object across the retina. The angular velocity is defined as:
$\omega = \frac{v_{\perp}}{r}$
where $v_{\perp}$ is the component of velocity perpendicular to the line of sight and $r$ is the radial distance between the observer and the object. [By Definition of Circular/Angular Motion].

Train Line of Sight Tree (Near) Moon (Far)

Step 3: Comparative Analysis of Near vs. Distant Objects

Feature Nearby Objects (Trees/Houses) Distant Objects (Moon/Stars)
Radial Distance ($r$) Small Extremely Large ($\rightarrow \infty$)
Angular Velocity ($\omega$) High ($\omega \approx \frac{v}{r_{small}}$) Negligible ($\omega \approx \frac{v}{r_{large}} \approx 0$)
Perception Rapid displacement across FOV Stationary relative to background

Step 4: Logical Derivation of the "Opposite Motion" Effect

  • Frame of Reference: When the observer is on the train, the observer assigns themselves a velocity of zero. To maintain physical consistency, an equal and opposite velocity ($-\vec{v}_{train}$) must be applied to all stationary external objects.
  • Nearby Objects: Because $r$ is small, the shift in angle ($\Delta\theta$) over a time interval ($\Delta t$) is large. This causes the objects to appear to sweep across the field of vision in the direction $-\vec{v}_{train}$.
  • Distant Objects: As $r \to \infty$, the term $\omega = \frac{v}{r} \to 0$. The objects do not change their angular position relative to the observer's line of sight, creating the illusion of being "fixed" in space.

Final Solution: The observation is a consequence of the inverse relationship between angular velocity and distance. Because nearby objects have a small radial distance ($r$), their angular velocity ($\omega = v/r$) is high, resulting in perceived rapid motion in the direction opposite to the train. Conversely, because distant objects have a near-infinite radial distance, their angular velocity is effectively zero, making them appear stationary relative to the observer.


More Questions from Class 11 Physics Units and Measurements EXERCISES


CBSE Solutions for Class 11 Physics Units and Measurements


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