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Q2.1(b):
Fill in the blanks (b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to ...(mm)$^2$

Solution :

Step 1: Given Variables and Unit Conversion

The dimensions of the cylinder are provided in centimeters ($cm$). We must convert these to millimeters ($mm$) to satisfy the requested output unit.

  • Radius ($r$) = $2.0\text{ cm}$
  • Height ($h$) = $10.0\text{ cm}$

Conversion factor: $1\text{ cm} = 10\text{ mm}$ [By metric prefix definition].

  • $r = 2.0 \times 10 = 20.0\text{ mm}$
  • $h = 10.0 \times 10 = 100.0\text{ mm}$

Step 2: Formula for Total Surface Area

The total surface area ($A$) of a solid cylinder is the sum of the areas of the two circular bases and the lateral (curved) surface area.

$A = 2\pi r^2 + 2\pi rh$ [Geometric Theorem for Cylinder Surface Area]

$A = 2\pi r(r + h)$

Step 3: Numerical Calculation

Substitute the values in $mm$ into the derived equation:

$A = 2 \times 3.14159 \times 20.0 \times (20.0 + 100.0)$

$A = 2 \times 3.14159 \times 20.0 \times 120.0$

$A = 125.6637 \times 120.0$

$A = 15079.644\text{ mm}^2$

Step 4: Significant Figure Analysis

The given data ($2.0\text{ cm}$ and $10.0\text{ cm}$) contain two and three significant figures, respectively. Following the rules of multiplication for significant figures [Per the rules of Arithmetic Operations with Measured Quantities], the final result should be restricted to the lowest number of significant figures provided, which is two.

$15079.644 \approx 1.5 \times 10^4\text{ mm}^2$

Geometric Visualization

r h

Final Solution: The surface area of the solid cylinder is approximately $1.5 \times 10^4\text{ mm}^2$.


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