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Q2.2(a):
Fill in the blanks by suitable conversion of units 1 (kg m^{2} s^{-2}) = ....(g cm^{2} s^{-2})

Solution :

Step 1: Identifying the Dimensional Quantity

The expression $1 \text{ kg m}^2 \text{ s}^{-2}$ represents the unit of energy (Joules) in the SI system [Per the definition of the Joule as a derived unit of work/energy].

Let the physical quantity be denoted by $Q$. The magnitude of this quantity can be expressed as:

$n_1 u_1 = n_2 u_2$

Where:

  • $n_1 = 1$ (the given numerical value in SI)
  • $u_1 = 1 \text{ kg} \cdot \text{m}^2 \cdot \text{s}^{-2}$
  • $n_2 = ?$ (the numerical value to be found)
  • $u_2 = 1 \text{ g} \cdot \text{cm}^2 \cdot \text{s}^{-2}$

Step 2: Dimensional Analysis

The dimensional formula for energy is $[M^1 L^2 T^{-2}]$. Using the principle of homogeneity of dimensions, we relate the two systems:

$n_2 = n_1 \left[ \frac{M_1}{M_2} \right]^a \left[ \frac{L_1}{L_2} \right]^b \left[ \frac{T_1}{T_2} \right]^c$

Given the dimensions $a=1, b=2, c=-2$, and applying unit conversions:

  • $M_1 = 1 \text{ kg} = 10^3 \text{ g}$
  • $L_1 = 1 \text{ m} = 10^2 \text{ cm}$
  • $T_1 = 1 \text{ s} = 1 \text{ s}$

Step 3: Numerical Calculation

Substitute the values into the conversion equation:

$n_2 = 1 \times \left( \frac{10^3 \text{ g}}{1 \text{ g}} \right)^1 \times \left( \frac{10^2 \text{ cm}}{1 \text{ cm}} \right)^2 \times \left( \frac{1 \text{ s}}{1 \text{ s}} \right)^{-2}$

Perform the algebraic operations [By the laws of exponents $x^a \cdot x^b = x^{a+b}$ and $(x^a)^b = x^{ab}$]:

$n_2 = 1 \times (10^3) \times (10^2)^2 \times (1)^{-2}$ $n_2 = 10^3 \times 10^4$ $n_2 = 10^7$

Visual Representation of Scale Conversion

1 kg·m²·s⁻² 10⁷ g·cm²·s⁻² Conversion Factor: × 10⁷

Step 4: Conclusion

By substituting the calculated numerical value back into the original equivalence statement:

$1 \text{ kg m}^2 \text{ s}^{-2} = 10^7 \text{ g cm}^2 \text{ s}^{-2}$

Final Solution: 1 (kg m^{2} s^{-2}) = 10^7 (g cm^{2} s^{-2})


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