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Q2.19:
The principle of ‘parallax’ in section 2.3.1 is used in the determination of distances of very distant stars. The baseline AB is the line joining the Earth’s two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth’s orbit $\approx 3 \times 10^{11}$m. However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of $1''$ (second) of arc or so. A parsec is a convenient unit of length on the astronomical scale. It is the distance of an object that will show a parallax of $1''$ (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres ?

Solution :

Step 1: Establishing the Geometric Configuration

The problem defines a parsec ($pc$) using the geometry of a small angle sector. The arc length ($b$) is the Astronomical Unit ($AU$), which is the mean distance between the Earth and the Sun, and the angle ($\theta$) subtended at the star is $1''$ (one second of arc). [Per the definition of angular diameter/arc length relationship: $s = r\theta$].

Step 2: Defining Constants and Units

  • Baseline ($b$) = $1 \text{ AU} \approx 1.496 \times 10^{11} \text{ m}$.
  • Angle ($\theta$) = $1''$ (second of arc).

Step 3: Conversion of Angular Units to Radians

To use the formula $s = r\theta$, the angle must be expressed in radians. Given the conversion factors: $1^\circ = (\pi/180) \text{ rad}$ $1' = (1/60)^\circ$ $1'' = (1/60)' = (1/3600)^\circ$

Therefore, $\theta = \left(\frac{1}{3600}\right) \times \left(\frac{\pi}{180}\right) \text{ radians}$ $\theta \approx \frac{3.14159}{648000} \approx 4.848 \times 10^{-6} \text{ rad}$ [By conversion of sexagesimal units to SI radians].

Step 4: Calculation of Parsec in Metres

Using the relation $D = \frac{b}{\theta}$, where $D$ is the distance in parsecs:

b = 1 AU D = 1 pc θ = 1"

Substituting the values: $D = \frac{1.496 \times 10^{11} \text{ m}}{4.848 \times 10^{-6} \text{ rad}}$ $D \approx 0.3086 \times 10^{17} \text{ m}$ $D \approx 3.086 \times 10^{16} \text{ m}$

Step 5: Tabulated Comparison of Astronomical Units

Unit Value in Metres (m)
1 Astronomical Unit (AU) $1.496 \times 10^{11}$
1 Parsec (pc) $3.086 \times 10^{16}$
1 Light Year (ly) $9.46 \times 10^{15}$

Final Solution: 1 parsec is approximately 3.086 × 10¹⁶ metres.


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