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Q2.13:
A physical quantity P is related to four observables a, b, c and d as follows : $P = \frac{a^3 b^2}{\sqrt{c} d}$ The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

Solution :

Step 1: Establishing the Error Propagation Formula

Given the physical relation: $P = \frac{a^3 b^2}{c^{1/2} d^1}$

According to the theory of propagation of errors for a quantity $Z = \frac{A^p B^q}{C^r D^s}$, the relative error is calculated as [Per the Law of Combination of Errors]:

$\frac{\Delta P}{P} = 3\left(\frac{\Delta a}{a}\right) + 2\left(\frac{\Delta b}{b}\right) + \frac{1}{2}\left(\frac{\Delta c}{c}\right) + 1\left(\frac{\Delta d}{d}\right)$

Step 2: Substitution of Given Percentage Errors

The percentage errors are given as:

  • $\left(\frac{\Delta a}{a} \times 100\right) = 1\%$
  • $\left(\frac{\Delta b}{b} \times 100\right) = 3\%$
  • $\left(\frac{\Delta c}{c} \times 100\right) = 4\%$
  • $\left(\frac{\Delta d}{d} \times 100\right) = 2\%$

Substituting these values into the percentage error equation:

$\frac{\Delta P}{P} \times 100 = 3(1\%) + 2(3\%) + \frac{1}{2}(4\%) + 1(2\%)$

$\frac{\Delta P}{P} \times 100 = 3\% + 6\% + 2\% + 2\% = 13\%$

Step 3: Determination of Significant Figures

The calculated percentage error is $13\%$. This implies the error is in the units place of the calculated value. To determine the rounding, we assess the precision of the calculated value $P = 3.763$.

As the percentage error is approximately $13\%$, the absolute error $\Delta P$ is:

$\Delta P = \frac{13}{100} \times 3.763 \approx 0.489$

Since the uncertainty exists in the first decimal place, the result must be rounded to one decimal place to maintain scientific consistency [Per the Rules of Significant Figures in Calculations].

Visual Representation of Error Magnitude

3.7 3.763 (Calculated P) 3.8

Step 4: Final Rounding

Given the value $3.763$ and the uncertainty suggesting the first decimal place is the limit of reliability, we round $3.763$ to the nearest tenth.

$3.763 \approx 3.8$

Final Solution: The percentage error in P is 13%, and the value should be rounded off to 3.8.


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