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Q6.11(iii):
How will you bring about the following conversions? (iii) Propene to 1-nitropropane

Solution :

Given Variables & Initial Setup

The objective is to convert Propene ($CH_3-CH=CH_2$) to 1-nitropropane ($CH_3-CH_2-CH_2-NO_2$).

The transformation requires a two-step process: first, the generation of a primary alkyl bromide (anti-Markovnikov addition), and second, a nucleophilic substitution reaction.

Step 1: Anti-Markovnikov Hydrobromination

To convert propene to 1-bromopropane, we must perform the addition of $HBr$ in the presence of an organic peroxide ($R_2O_2$). This mechanism proceeds via a free radical pathway, ensuring that the bromine atom attaches to the less substituted carbon atom [Per Kharasch effect or Peroxide Effect].

$CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2-Br$

  • Reagent: $HBr$ / Benzoyl peroxide.
  • Justification: In the presence of peroxides, the reaction follows the free radical mechanism where the secondary radical is more stable than the primary radical, leading to the anti-Markovnikov product.

Step 2: Nucleophilic Substitution with Silver Nitrite

To convert 1-bromopropane into 1-nitropropane, the bromide ion is displaced by the nitrite ion ($NO_2^-$). Using silver nitrite ($AgNO_2$) is essential here because $AgNO_2$ is primarily covalent; the nitrogen atom acts as the nucleophile, favoring the formation of a nitroalkane over an alkyl nitrite [Per the ambident nucleophile theory of the nitrite ion].

$CH_3-CH_2-CH_2-Br + AgNO_2 \xrightarrow{\Delta, Ethanol/Water} CH_3-CH_2-CH_2-NO_2 + AgBr$

  • Reagent: $AgNO_2$ (Silver nitrite).
  • Justification: The use of $AgNO_2$ ensures the linkage occurs through the nitrogen atom due to its covalent character, resulting in the nitro compound ($R-NO_2$). If $KNO_2$ were used, the ionic character would favor oxygen as the nucleophile, resulting in an alkyl nitrite ($R-O-N=O$).

Reaction Sequence Visualization

Propene HBr, Peroxide 1-Bromopropane AgNOβ‚‚ 1-Nitropropane

Summary of Reaction Conditions

Transformation Step Reagents Used Mechanism Type
Propene $\rightarrow$ 1-Bromopropane $HBr$, $R_2O_2$ Free Radical Addition
1-Bromopropane $\rightarrow$ 1-Nitropropane $AgNO_2$ $S_N2$ Nucleophilic Substitution

Final Solution: The conversion is achieved via Anti-Markovnikov addition of $HBr$ to propene to form 1-bromopropane, followed by nucleophilic substitution with $AgNO_2$ to yield 1-nitropropane ($CH_3CH_2CH_2NO_2$).


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