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Q6.1(viii):
Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides: (viii) \(CH_{3}CH=C(Cl)CH_{2}CH(CH_{3})_{2}\)

Solution :

Step 1: Structural Analysis and Identification

The given compound is $CH_{3}CH=C(Cl)CH_{2}CH(CH_{3})_{2}$. To determine the IUPAC name, we must first identify the longest carbon chain containing the double bond and the chlorine substituent.

  • The chain consists of 6 carbon atoms (a hexane derivative).
  • Numbering the chain must prioritize the alkene group [Per IUPAC Nomenclature Rule: Select the principal functional group with the lowest possible locant].
  • Numbering from left to right: $C_1(H_3) - C_2(H) = C_3(Cl) - C_4(H_2) - C_5(H)(CH_3) - C_6(H_3)$.
  • The double bond starts at position $C_2$, and the chlorine is attached to $C_3$. A methyl branch is present at position $C_5$.

Step 2: IUPAC Nomenclature Formulation

Based on the structure:

  • Principal chain: Hex-2-ene.
  • Substituents: 3-chloro and 5-methyl.
  • Alphabetical order: "Chloro" precedes "methyl" [Per IUPAC Rule: substituents are cited alphabetically].
  • Combined Name: 3-chloro-5-methylhex-2-ene.

Step 3: Classification of the Halide

To classify the halide, observe the carbon atom directly bonded to the chlorine atom ($C_3$):

  • The carbon $C_3$ is bonded to a double-bonded carbon ($C_2$).
  • According to classification standards, if the halogen atom is attached to a carbon atom that is part of a carbon-carbon double bond ($C=C$), it is classified as a vinylic halide.

Step 4: Molecular Visualization

CH₃ CH C Cl CH₂ CH CH₃ CH₃

Summary Table

Attribute Result
IUPAC Name 3-Chloro-5-methylhex-2-ene
Classification Vinyl Halide

Final Solution: The compound is 3-Chloro-5-methylhex-2-ene and is classified as a vinylic halide.


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