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Q4.20 (i):
Compare the chemistry of actinoids with that of the lanthanoids with special reference to: (i) electronic configuration

Solution :

1. Theoretical Foundations of Electronic Configuration

The electronic configuration of lanthanoids (Ln) and actinoids (Ac) is governed by the filling of $4f$ and $5f$ orbitals, respectively. Both series represent the inner transition elements, where the $f$-orbitals are progressively filled according to the Aufbau principle, modified by the relative energies of $f$, $d$, and $s$ subshells.

2. Comparative Analysis of Electronic Configurations

The general electronic configuration for these series can be expressed as follows:

  • Lanthanoids: $[Xe] \, 4f^{1-14} \, 5d^{0-1} \, 6s^2$
  • Actinoids: $[Rn] \, 5f^{0-14} \, 6d^{0-2} \, 7s^2$

3. Key Distinctions in Orbital Participation

Feature Lanthanoids (Ln) Actinoids (Ac)
Orbital Energy Gap The $4f$ electrons are deeply buried; they participate minimally in bonding. The $5f$, $6d$, and $7s$ energy levels are closer in energy, allowing $5f$ electrons to participate in bonding.
Effective Shielding $4f$ electrons provide poor shielding, leading to lanthanoid contraction. $5f$ electrons provide even poorer shielding than $4f$ electrons, leading to a more pronounced actinoid contraction.
Oxidation States Predominantly $+3$. Highly variable (ranging from $+3$ to $+7$) due to the availability of $5f$ and $6d$ electrons.

4. Visual Representation: Relative Energy States

Orbital Progression Energy 4f (Stable) 5f, 6d (Available)

5. Detailed Logical Summary

The primary distinction in electronic configuration is the spatial distribution and energy accessibility. In lanthanoids, the $4f$ orbitals are shielded by the $5s^2$ and $5p^6$ shells, rendering the $4f$ electrons chemically inert [Per Slater's Rules regarding shielding efficacy]. Conversely, in actinoids, the $5f$ orbitals extend further from the nucleus compared to $4f$ orbitals, facilitating overlap with ligand orbitals and enabling higher oxidation states [Justified by the radial distribution functions of $5f$ vs $4f$ orbitals].

Final Solution: While lanthanoids predominantly exhibit a stable $+3$ oxidation state due to the deep burial of $4f$ electrons, the actinoids show a wider range of oxidation states because the $5f$, $6d$, and $7s$ electrons are of comparable energy levels, allowing for more complex bonding interactions.


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