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Q4.23:
Which metal in the first series of transition metals exhibits +1 oxidation state most frequently and why?

Solution :

Step 1: Analyzing the First Transition Series

The first transition series (3d series) consists of elements from Scandium ($Sc, Z=21$) to Zinc ($Zn, Z=30$). The electronic configurations follow the general pattern $[Ar] 3d^{n} 4s^{2}$, with exceptions for Chromium ($3d^{5} 4s^{1}$) and Copper ($3d^{10} 4s^{1}$).

Step 2: Identifying the Metal

Among the elements of the first transition series, Copper ($Cu$) is the only element that exhibits a stable $+1$ oxidation state frequently ($Cu^{+}$).

Step 3: Electronic Configuration and Stability Analysis

The ground state electronic configuration of Copper is $[Ar] 3d^{10} 4s^{1}$.

When Copper loses one electron to form the $Cu^{+}$ ion, its configuration becomes:

$Cu^{+} = [Ar] 3d^{10}$

[Per the Aufbau Principle and Hund’s Rule, a completely filled d-subshell confers exceptional electronic stability to the ion.]

Step 4: Energetic Justification

The stability of an oxidation state in aqueous solution is determined by the balance between the Ionization Enthalpy required to remove electrons and the Hydration Enthalpy released when the ion is solvated.

  • While $Cu^{+}$ has a stable $3d^{10}$ configuration, it is often unstable in aqueous solutions because it undergoes disproportionation: $2Cu^{+}(aq) \rightarrow Cu^{2+}(aq) + Cu(s)$
  • However, $Cu^{+}$ is frequently observed in solid-state compounds and in specific complexes where the high hydration energy of $Cu^{2+}$ (which usually favors $Cu^{2+}$ in water) is offset by lattice energy or specific ligand-field stabilization effects.

Step 5: Visual Representation of Electron Distribution

3d¹⁰ Cu⁺ Configuration: [Ar] 3d¹⁰

Summary Table of Oxidation States

Metal Common Oxidation States Stability Factor
Copper ($Cu$) $+1, +2$ $3d^{10}$ configuration makes $+1$ accessible.
Other 3d Metals $+2, +3$ (predominant) Higher states are favored by d-orbital vacancy.

Final Solution: Copper ($Cu$) is the metal that exhibits the $+1$ oxidation state most frequently because the loss of the single $4s$ electron results in a stable, completely filled $3d^{10}$ electronic configuration.


More Questions from Class 12 Chemistry The d- and f-Block Elements Exercises


CBSE Solutions for Class 12 Chemistry The d- and f-Block Elements


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