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Q4.1 (vii):
Write down the electronic configuration of: (vii) Mn^{2+}

Solution :

Step 1: Identifying the Atomic Number and Ground State Configuration

To determine the electronic configuration of $Mn^{2+}$, we first identify the atomic number ($Z$) of Manganese ($Mn$). Manganese is located in the 3d transition series with an atomic number of $Z = 25$.

The ground state electronic configuration for a neutral Manganese atom ($Mn^0$) is determined by the Aufbau Principle, which states that electrons fill orbitals in order of increasing energy: $1s \to 2s \to 2p \to 3s \to 3p \to 4s \to 3d$. [Per the Aufbau Principle]

The configuration for $Mn$ ($Z=25$) is:
$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5$
Or, using noble gas notation: $[Ar] 3d^5 4s^2$.

Step 2: Accounting for Ionization ($Mn^{2+}$)

The formation of a cation involves the loss of electrons from the orbitals with the highest principal quantum number ($n$). [Per the orbital energy hierarchy in transition metals]

For the transition metal $Mn$, the $4s$ orbital has a higher principal quantum number ($n=4$) compared to the $3d$ orbital ($n=3$). Therefore, electrons are removed from the $4s$ subshell before the $3d$ subshell during the ionization process.

To obtain $Mn^{2+}$, we must remove two electrons from the neutral $Mn$ atom:

  • Removal of the first electron from the $4s$ orbital.
  • Removal of the second electron from the $4s$ orbital.

Step 3: Final Configuration Derivation

Subtracting two electrons from the $4s$ subshell of $[Ar] 3d^5 4s^2$ yields the resulting configuration:
$Mn^{2+} = [Ar] 3d^5 4s^0$

This is commonly simplified to:
$Mn^{2+} = [Ar] 3d^5$

Visual Representation of d-Orbital Filling

3d-orbitals (singly occupied: Hund's Rule)

Final Solution: The electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$.


More Questions from Class 12 Chemistry The d- and f-Block Elements Exercises


CBSE Solutions for Class 12 Chemistry The d- and f-Block Elements


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