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Q4.25(iii):
Give examples and suggest reasons for the following features of the transition metal chemistry: (iii) The highest oxidation state is exhibited in oxoanions of a metal.

Solution :

Theoretical Foundation: The Role of Oxygen in Stabilizing High Oxidation States

The stability of high oxidation states in transition metals is fundamentally linked to the electronegativity and the lattice/bond energy provided by the oxygen atom. Oxygen, being a small, highly electronegative element, is capable of stabilizing metal atoms in their highest possible oxidation states through $p\pi-d\pi$ multiple bonding [Per the principles of Hard-Soft Acid-Base Theory and valence bond theory].

Step 1: Identifying Representative Examples

The following table lists prominent transition metals exhibiting their maximum group oxidation state within oxoanion structures:

Oxoanion Central Metal Oxidation State Calculation Resulting State
$MnO_4^-$ Manganese ($Mn$) $x + 4(-2) = -1 \implies x = +7$ $+7$
$CrO_4^{2-}$ Chromium ($Cr$) $x + 4(-2) = -2 \implies x = +6$ $+6$
$VO_4^{3-}$ Vanadium ($V$) $x + 4(-2) = -3 \implies x = +5$ $+5$

Step 2: Analytical Justification of the Phenomenon

The preference for oxoanions to house high oxidation states is governed by the following factors:

  • Electronegativity: Oxygen possesses a high electronegativity ($3.44$ on the Pauling scale). This creates a highly polar $M-O$ bond, effectively pulling electron density away from the metal center, which minimizes the repulsive forces associated with the electron-deficient metal cation.
  • $p\pi-d\pi$ Bonding: Oxygen utilizes its lone pairs of electrons to form $\pi$-bonds with the empty or partially filled $d$-orbitals of the transition metal. This covalent contribution stabilizes the high positive charge density on the metal [By the Molecular Orbital Theory of oxoanions].
  • Size and Charge Density: Oxygen atoms are small and effectively pack around the transition metal, creating a stable coordination environment that mitigates the high charge density through an extended lattice or molecular network.

Step 3: Visual Representation of $MnO_4^-$ Geometry

Mn (+7) O (-2) O (-2) O (-2) O (-2)

Final Solution: The highest oxidation states of transition metals are observed in oxoanions (e.g., $MnO_4^-$) because the high electronegativity of oxygen and its ability to participate in $p\pi-d\pi$ multiple bonding effectively stabilize the highly positive metal center, a condition that cannot be sustained by less electronegative or larger ligands.


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