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Q13(iii):
A die is thrown once. Find the probability of getting (iii) an odd number.

Solution :

Given: A fair six-faced die is thrown once. The possible outcomes are the integers from 1 to 6.

To Find: The probability of getting an odd number.

Step 1: Defining the Sample Space
Let $S$ be the sample space representing all possible outcomes when a die is thrown. Since a standard die has six faces numbered 1 through 6:
$S = \{1, 2, 3, 4, 5, 6\}$
The total number of possible outcomes, denoted by $n(S)$, is:
$n(S) = 6$

Step 2: Defining the Event
Let $E$ be the event of getting an odd number. An odd number is an integer that is not divisible by 2. From the sample space $S$, we identify the odd numbers:
$E = \{1, 3, 5\}$
The number of favorable outcomes, denoted by $n(E)$, is:
$n(E) = 3$

Step 3: Applying the Probability Formula
The probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes in the sample space:
$P(E) = \frac{n(E)}{n(S)}$
[Using the classical definition of probability for equally likely outcomes]

Step 4: Calculation
Substitute the values obtained in Step 1 and Step 2 into the formula:
$P(E) = \frac{3}{6}$
To simplify the fraction, divide both the numerator and the denominator by their greatest common divisor, which is 3:
$P(E) = \frac{3 \div 3}{6 \div 3} = \frac{1}{2}$

Final Answer: The probability of getting an odd number is $\frac{1}{2}$ (or 0.5).


More Questions from Class 10 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 10 Mathematics Probability


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