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Q10(i):
A piggy bank contains hundred 50p coins, fifty ` 1 coins, twenty ` 2 coins and ten ` 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin ?

Solution :

Given:

The contents of the piggy bank are as follows:

  • Number of 50p coins = $100$
  • Number of ₹1 coins = $50$
  • Number of ₹2 coins = $20$
  • Number of ₹5 coins = $10$

To Find:

The probability that the coin that falls out is a 50p coin.


Step 1: Calculating the Total Number of Possible Outcomes

The total number of outcomes is the sum of all the coins present in the piggy bank. Let $n(S)$ be the total number of coins.

$n(S) = (\text{Number of 50p coins}) + (\text{Number of ₹1 coins}) + (\text{Number of ₹2 coins}) + (\text{Number of ₹5 coins})$

$n(S) = 100 + 50 + 20 + 10$

$n(S) = 180$

[Since the total number of elementary events in the sample space is the sum of all individual coin counts.]


Step 2: Identifying the Number of Favorable Outcomes

Let $E$ be the event that the coin falling out is a 50p coin. Let $n(E)$ be the number of favorable outcomes.

$n(E) = \text{Number of 50p coins}$

$n(E) = 100$


Step 3: Applying the Probability Formula

The probability of an event $P(E)$ is defined by the ratio of the number of favorable outcomes to the total number of possible outcomes:

$P(E) = \frac{n(E)}{n(S)}$

[Using the classical definition of probability for equally likely outcomes.]


Step 4: Calculation and Simplification

$P(E) = \frac{100}{180}$

To simplify the fraction, we divide both the numerator and the denominator by their greatest common divisor, which is $20$:

$P(E) = \frac{100 \div 20}{180 \div 20}$

$P(E) = \frac{5}{9}$


Final Answer: The probability that the coin will be a 50p coin is $\frac{5}{9}$.


More Questions from Class 10 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 10 Mathematics Probability


Chapters in CBSE - Class 10 Mathematics


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