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Q4:

Which of the following cannot be the probability of an event?

Solution :

Given: A set of values representing potential probabilities of an event: (A) $2/3$, (B) $-1.5$, (C) $15\%$, (D) $0.7$.

To Find: Identify which of the given values cannot represent the probability of an event.

Theoretical Background:

In the theory of probability, for any event $E$, the probability $P(E)$ must satisfy the following fundamental axiom:

$0 \leq P(E) \leq 1$

This implies that:

1. The probability of an event cannot be negative ($P(E) \geq 0$).

2. The probability of an event cannot exceed $1$ ($P(E) \leq 1$).

Step 1: Analyzing the given options

We evaluate each option against the condition $0 \leq P(E) \leq 1$.

Option Value Decimal Equivalent Validity ($0 \leq P \leq 1$)
(A) $2/3$ $\approx 0.66$ Valid
(B) $-1.5$ $-1.5$ Invalid
(C) $15\%$ $0.15$ Valid
(D) $0.7$ $0.7$ Valid

Step 2: Justification for the invalid value

The value $-1.5$ is less than $0$. Since the probability of an event is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes, it must always be a non-negative value. Therefore, a negative value is mathematically impossible for a probability.

Conclusion:

Since $-1.5 < 0$, it violates the axiom $P(E) \geq 0$. Thus, it cannot be the probability of an event.

Final Answer: The value that cannot be the probability of an event is -1.5.


More Questions from Class 10 Mathematics Probability EXERCISE 14.1


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