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Q10(ii):
A piggy bank contains hundred 50p coins, fifty ` 1 coins, twenty ` 2 coins and ten ` 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (ii) will not be a ` 5 coin?

Solution :

Given:

The contents of the piggy bank are as follows:

  • Number of 50p coins = $100$
  • Number of ₹1 coins = $50$
  • Number of ₹2 coins = $20$
  • Number of ₹5 coins = $10$

To Find:

The probability that the coin falling out will not be a ₹5 coin.

Step 1: Calculate the total number of possible outcomes.

The total number of outcomes is the sum of all the coins in the piggy bank.

Total number of coins = $100 + 50 + 20 + 10$

Total number of coins = $180$

[Since the total number of elementary events in the sample space is the sum of all individual coin counts]

Step 2: Identify the number of favorable outcomes.

We are looking for the probability that the coin is not a ₹5 coin. This is the complement of the event that the coin is a ₹5 coin.

Let $E$ be the event that the coin is a ₹5 coin.

Number of favorable outcomes for $E$ = $10$

Let $E'$ be the event that the coin is not a ₹5 coin.

Number of favorable outcomes for $E'$ = (Total number of coins) - (Number of ₹5 coins)

Number of favorable outcomes for $E'$ = $180 - 10 = 170$

[Alternatively, sum of all coins except ₹5 coins: $100 + 50 + 20 = 170$]

Step 3: Apply the Probability Formula.

The probability of an event $A$ is given by the formula:

$P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

[Definition of Probability for equally likely outcomes]

Substituting the values for event $E'$:

$P(E') = \frac{170}{180}$

Step 4: Simplify the fraction.

$P(E') = \frac{170 \div 10}{180 \div 10}$

$P(E') = \frac{17}{18}$

Alternative Method (Using Complementary Events):

We know that $P(E') = 1 - P(E)$.

$P(E) = \frac{10}{180} = \frac{1}{18}$

$P(E') = 1 - \frac{1}{18}$

$P(E') = \frac{18 - 1}{18} = \frac{17}{18}$

[Since the sum of the probability of an event and its complement is 1]

Final Answer: The probability that the coin will not be a ₹5 coin is $\frac{17}{18}$.


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