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Q5:
If $P(E) = 0.05$, what is the probability of ‘not $E$’?

Solution :

Given: The probability of an event $E$ occurring is $P(E) = 0.05$.

To Find: The probability of the event 'not $E$', denoted as $P(\text{not } E)$ or $P(\overline{E})$.

Theoretical Foundation:
In probability theory, for any event $E$, the event 'not $E$' represents the complement of event $E$. The sum of the probability of an event and the probability of its complement is always equal to $1$. This is expressed by the formula:
$P(E) + P(\overline{E}) = 1$
where $P(\overline{E})$ is the probability of the event 'not $E$'.

Step 1: Setting up the equation
Let $P(E)$ be the probability of the event occurring and $P(\overline{E})$ be the probability of the event not occurring.
Given $P(E) = 0.05$.
Substituting the known value into the complement probability formula:
$0.05 + P(\overline{E}) = 1$

Step 2: Solving for $P(\overline{E})$
To isolate $P(\overline{E})$, we subtract $0.05$ from both sides of the equation:
$P(\overline{E}) = 1 - 0.05$

Step 3: Performing the arithmetic subtraction
Aligning the decimal points for subtraction:
$1.00 - 0.05 = 0.95$
Therefore, $P(\overline{E}) = 0.95$.

Final Answer: The probability of 'not $E$' is 0.95.


More Questions from Class 10 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 10 Mathematics Probability


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