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Lesson Posted on 23/11/2022 Learn CBSE
Vidhi Gaba
I am a tutor since past 5 years and have an experience in the language for over 11years now. I have been...
The basic conversational building blocks are a great place to start. Simple phrases like good morning, how are you, etc. grease the wheels of daily conversation in most every language, including Spanish.
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Answered on 23/03/2020 Learn Class IX-X Tuition
Apoorva P.
Mohandas Karamchand Gandhi started the non-cooperation movement. The main motive of this movement was to resist the British rule in India, by a non-violent means, also called "satyagraha". This movement gained widespread popularity and was spread across the countryside.
This was a mass movement followed in the urban cities and towns, by the people who used to look up to Gandhi and his methods of agitation.
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Lesson Posted on 18/07/2017 Learn German Language
Priya Puranik
I have teaching experience of more than 6 years. I started taking German classes as a student and have...
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Lesson Posted on 18/06/2017 Learn Class IX-X Tuition
Numerical problems on force and pressure
Soumi Roy
I am an experienced, qualified tutor with over 8 years of experience in teaching maths and Science across...
Example 1:
A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?
Given:
Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2
Thrust = Normal pressure = F = 1200 N
Pressure P = F/A 1200N10−3m21200N10−3m2
= 1.2 ×× 106 N/m2
Example 2:
The elephant weighs 20,000 N stands on one foot of area 1000 cm2. How much pressure would it exert on the ground?
Given:
Force applied by elephant F = 20,000 N, area A = 1000 cm2 = 1000/100×100m2 = 0.1 m2
The pressure is given by
Pressure P = F/A
= 20,000N/0.1m2
= 2,00,000 N/m2.
Example 3:
Calculate the pressure produced by a force of 800 N acting on an area of 2.0 m2.
Solution:
Pressure is defined as force per unit area or P = F / A
P = (800 N) / (2.0 m2
)
P = 400 N / m2
= 400 Pa
Example 4:
The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m2. Calculate the force that is exerted on the piston.
Solution
Pressure is defined as force per unit area or P = F / A
We multiply both sides of the equation by the area to solve for the force as
F = P A
F = (300 Pa) (0.5 m2
)
F = 150 (Pa) m2
= 150 (N / m2
) m2
F = 150 N
Example 5:
A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
Solution:
The pressure due to a column of fluid is calculated as the product of the height of the fluid times
the density of the fluid times the acceleration due to gravity. For water the density is d = 1000 kg /
m3
.
? P = d h g
? P = (1000 kg / m3
) (3.0 m) (9.8 m / s2
)
? P = 29400 kg m2 / m3
s2
To simplify the units we cancel one m term in the m2
term in the numerator and one m term in
the m3
term in the denominator to get
? P = 29400 kg m / s2
m2
We know that 1N = 1 kg m / s2
so we can write
? P = 29400 N / m2
= 29400 Pa
Answered on 05/12/2023 Learn Class IX-X Tuition
Ashutosh Singh
BTech, ECE tutor near Dwarka Sector 22
Hey,
Let's find the y intercept of the line: -4x + 6y = -12?
In the equation ax + by = c
, the y-intercept is the point where the line crosses the y-axis. To find the y-intercept, we can set x = 0
and solve for y
.
Let’s solve the equation for y
:
Given that: ax + by =c
Deviding both the sides by constant 'b', we get: y = (c/b) - (a/b)x,
To find y intercept put x = 0, we get: y = (c/b) - (a/b)*0 = c/b
Now, comparing -4x + 6y = 12 with general equation ax + by = c, we get: a = -4, b = 6 & c = -12
Therefore: y = -12/6 = -2
Plot is attached.
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Answered on 12 Apr Learn Class IX-X Tuition
Raman Kansal
Senior Physics Faculty with specialization in JEE(Mains&Advanced)/NEET/CBSE/ISC/IB/IGCSE/AP
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Answered on 20/11/2023 Learn Class IX-X Tuition
Mangesh Gore
Math teacher since 8+ years
in the context of refraction, the apparent position refers to the location of an object as observed by an observer, taking into account the bending of light rays due to refraction through different mediums. It's the position where the object appears to be.
On the other hand, the actual position refers to the true or real location of the object, unaffected by the refraction of light. This is where the object physically exists, independent of any optical effects caused by the bending of light rays.
Refraction causes the apparent position to differ from the actual position due to the bending of light as it travels from one medium to another, like air to water or air to glass.
read lessAnswered on 20/11/2023 Learn Class IX-X Tuition
Kotha Harika
Software Trainer with 12 years of IT experience
Answered on 29 Jan Learn Class IX-X Tuition
Hemanth Kumar S
I'm a professor with more than 6 years of experiences.
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Answered on 08/01/2015 Learn Class IX-X Tuition
Manohar P.
Home Tuitor for Class V to X,Computer,Speaking English,CBSE, ICSE & State Board
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