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Popular Courses in Thiruvananthapuram
Foundary Nuke
By Vivek.K.GVisual effects VFXPattom Palace, Thiruvananthapuram
After this course you will be able to do almost all types of vfx related works including rotoscopy, compositing, wire removal, 3d tracking etc. It is an... Read More
Angel Therapy
By Arjun RadhakrishnanSpiritual WorkshopKunnukuzhy, Thiruvananthapuram
*few Ascended Masters Energy will be transmitted to you in the Angel Therapy class, besides energies of Archangels. 1. Working with Ascended MastersIn... Read More
Introduction to Programming
By VysakhCoding for KidsPappanamcode, Thiruvananthapuram
It is comprehensive lesson of Python programming that would give basic idea about python programming. Students would be able to do algebraic operations,... Read More
BSc Physics
By VysakhBSc TuitionPappanamcode, Thiruvananthapuram
Here is the ultimate solution to those who have trouble with the courses in BSc Physics. In my lectures I would explain the concepts in a comprehensive... Read More
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Show previous answers 
Manish Rahatekar replied | 10 hrs ago
Hi, I always suggest 2 books by author Prakash Iyer - Habit Of Winning & The Secret of Leadership and Atomic habits by James Clear...these help in building vocabulary, are simple to read, easy to understand and very practical. Hope you like them.
Aiswarya Harikumar replied | 14 hrs ago
B) Accentuating the space between the main beats
Fatima Khan Pathan replied | 2 days ago
For the ellipse
x²/16 + y²/9 = 1
Here, a = 4 and b = 3.
Area = πab = π × 4 × 3 = 12π square units ≈ 37.7 square units.
Mahinoor Banu replied | 10 hrs ago
Center: $(0, 0)$
Orientation: Horizontal major axis (along the x-axis, as $16 > 9$)
Semi-Major Axis ($a$): $4$ (since $a^2 = 16$)
Semi-Minor Axis ($b$): $3$ (since $b^2 = 9$)
Focal Distance ($c$): $\sqrt{a^2 - b^2} = \sqrt{16 - 9} = \sqrt{7} \approx 2.65$
Major Axis Vertices: $(\pm 4, 0)$
Minor Axis Vertices (Co-vertices): $(0, \pm 3)$
Foci: $(\pm\sqrt{7}, 0)$
Length of Major Axis: $2a = 8$
Length of Minor Axis: $2b = 6$
Eccentricity ($e$): $\frac{c}{a} = \frac{\sqrt{7}}{4} \approx 0.661$
Directrices: $x = \pm\frac{a^2}{c} = \pm\frac{16}{\sqrt{7}}$
Length of Latus Rectum: $\frac{2b^2}{a} = \frac{2(9)}{4} = \frac{9}{2} = 4.5$
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Hema Singh replied | 3 days ago
Spoken english by Neetu Singh mam available online too