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Q4:
What would be the molar concentration of human DNA in a human cell? Consult your teacher.

Solution :

Step 1: Establishing Quantitative Parameters of Human Genomic DNA

To calculate the molar concentration of DNA within a single human cell, we must first establish the physical mass of the haploid/diploid genome and the average molecular weight of a base pair. The calculation follows these standard biophysical constants:

  • Genome size (diploid): The human diploid cell contains approximately $6.6 \times 10^9$ base pairs (bp).
  • Average molecular weight of a nucleotide pair: $660 \text{ Daltons (g/mol)}$.
  • Avogadro’s Constant ($N_A$): $6.022 \times 10^{23} \text{ molecules/mol}$.

Step 2: Calculating the Total Mass of DNA per Cell

The total molecular weight ($MW$) of the DNA content in a single diploid human cell is determined by the product of the number of base pairs and the average mass per base pair:

$MW = (6.6 \times 10^9 \text{ bp}) \times (660 \text{ g/mol/bp})$

$MW = 4.356 \times 10^{12} \text{ g/mol}$

Step 3: Calculating the Mass of DNA in Grams

To find the mass ($m$) of DNA in a single cell, we divide the total molecular weight by Avogadro’s constant:

$m = \frac{4.356 \times 10^{12} \text{ g/mol}}{6.022 \times 10^{23} \text{ molecules/mol}}$

$m \approx 7.23 \times 10^{-12} \text{ grams}$

[Per the definition of the mole and molecular mass, $1 \text{ mole} = N_A \text{ molecules}$. Thus, mass per cell = $MW / N_A$].

Step 4: Defining the Cellular Volume (Micro-environment)

The molar concentration depends on the volume ($V$) in which the DNA is contained. In a human cell, DNA is sequestered within the nucleus. The average volume of a human nucleus is approximately $100 \text{ } \mu m^3$ to $500 \text{ } \mu m^3$. We shall utilize a standard estimate of $200 \text{ } \mu m^3$ ($200 \times 10^{-15} \text{ L}$ or $2 \times 10^{-13} \text{ L}$).

Step 5: Determining Molar Concentration ($C$)

Molar concentration is defined as the number of moles ($n$) per unit volume ($V$).

$n = \frac{\text{Number of DNA molecules (1)}}{\text{Avogadro's Constant (} N_A \text{)}}$

$n = \frac{1}{6.022 \times 10^{23}} \approx 1.66 \times 10^{-24} \text{ moles}$

Applying the concentration formula $C = \frac{n}{V}$:

$C = \frac{1.66 \times 10^{-24} \text{ moles}}{2 \times 10^{-13} \text{ L}}$

$C \approx 8.3 \times 10^{-12} \text{ M}$

Human Cell (Volume V) Nucleus (DNA) C ≈ 8.3 x 10⁻¹² M

Final Solution: The molar concentration of DNA in a human cell is approximately $8.3 \times 10^{-12} \text{ M}$ (or $8.3 \text{ pM}$), given an average nuclear volume of $200 \text{ } \mu m^3$. Note that this value varies significantly based on cellular ploidy, nuclear condensation states, and cell-specific nuclear volumes.


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