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Q10.3(e):
Fill in the blanks using the word(s) from the list appended with each statement: (e) For the model of a plane in a wind tunnel, turbulence occurs at a ... speed for turbulence for an actual plane (greater / smaller)

Solution :

Step 1: Theoretical Foundation of Reynolds Number

The transition from laminar flow to turbulent flow in a fluid is governed by the dimensionless quantity known as the Reynolds number ($Re$), defined by the expression:

$Re = \frac{\rho v D}{\eta}$

Where:

  • $\rho$ = Density of the fluid [kg/m³]
  • $v$ = Flow velocity of the fluid [m/s]
  • $D$ = Characteristic linear dimension (characteristic length of the object) [m]
  • $\eta$ = Dynamic viscosity of the fluid [Pa·s]

[Per the principle of dynamic similarity in fluid mechanics, the flow regime transition occurs at a specific critical Reynolds number ($Re_c$).]

Step 2: Comparison of Model and Actual Plane

For both the scale model in the wind tunnel and the actual plane in flight, the fluid medium (air) remains the same, implying $\rho$ and $\eta$ are constant across both scenarios. To maintain dynamic similarity (i.e., to have the same $Re$ for the model and the actual plane), the following relationship must hold:

$v_m D_m = v_a D_a$

Where subscript '$m$' denotes the model and '$a$' denotes the actual plane.

Step 3: Analytical Derivation of Velocity

Rearranging the equation to solve for the velocity $v$:

$v = \frac{Re_c \cdot \eta}{\rho \cdot D}$

From this equation, it is evident that velocity $v$ is inversely proportional to the characteristic dimension $D$ ($v \propto \frac{1}{D}$).

Since the scale model of a plane is significantly smaller than the actual plane ($D_m \ll D_a$), it mathematically follows that the velocity required to reach the critical Reynolds number for the model must be significantly higher than the velocity required for the actual plane.

Step 4: Visualizing Fluid Flow Regimes

Small Object (Model) Requires higher velocity (v) for turbulence Large Object (Actual Plane) Requires lower velocity (v) for turbulence

Step 5: Final Logical Deduction

Because the dimension $D$ for the model is smaller, the denominator in the proportionality $v \propto \frac{1}{D}$ decreases, forcing $v$ to increase to maintain the same critical $Re$ at which turbulence initiates. Therefore, the model reaches turbulence at a greater speed compared to the speed at which the actual plane would transition to turbulence under identical fluid conditions.

Final Solution: For the model of a plane in a wind tunnel, turbulence occurs at a greater speed for turbulence for an actual plane.


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