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Q10.12:
Does it matter if one uses gauge instead of absolute pressures in applying Bernoulli’s equation ? Explain.

Solution :

Step 1: Theoretical Statement of Bernoulli’s Equation

Bernoulli’s principle for an incompressible, non-viscous, steady flow of a fluid is expressed as:

$P + \frac{1}{2}\rho v^2 + \rho gh = \text{constant}$

Where:

  • $P$ is the pressure of the fluid.
  • $\rho$ is the density of the fluid.
  • $v$ is the velocity of the fluid.
  • $h$ is the height above a reference plane.

Step 2: Comparison of Gauge vs. Absolute Pressure

By definition, absolute pressure ($P_{abs}$) is related to gauge pressure ($P_g$) and atmospheric pressure ($P_{atm}$) by the relation [Per Pascal’s Law and Hydrostatic Principles]:

$P_{abs} = P_g + P_{atm}$

Step 3: Substitution into Bernoulli’s Equation

If we apply Bernoulli’s equation between two distinct points (1 and 2) in a streamline, we write:

$P_{abs,1} + \frac{1}{2}\rho v_1^2 + \rho gh_1 = P_{abs,2} + \frac{1}{2}\rho v_2^2 + \rho gh_2$

Substituting the gauge pressure definition into both sides:

$(P_{g,1} + P_{atm}) + \frac{1}{2}\rho v_1^2 + \rho gh_1 = (P_{g,2} + P_{atm}) + \frac{1}{2}\rho v_2^2 + \rho gh_2$

Step 4: Algebraic Simplification

Subtracting $P_{atm}$ from both sides of the equation yields:

$P_{g,1} + \frac{1}{2}\rho v_1^2 + \rho gh_1 = P_{g,2} + \frac{1}{2}\rho v_2^2 + \rho gh_2$

[By the Additive Property of Equality in Algebraic Fields].

Step 5: Visual Representation of Pressure Components

Reference Plane $P_{abs}$ $= P_{gauge} + P_{atm}$

Analytical Conclusion

Since the atmospheric pressure $P_{atm}$ appears as an additive constant on both sides of the equation, it cancels out mathematically. Therefore, it does not matter whether one uses gauge pressure or absolute pressure when applying Bernoulli’s equation, provided that the same reference (either absolute or gauge) is used for all pressure terms in the equation.

Final Solution: It does not matter whether gauge or absolute pressure is used in Bernoulli's equation because the atmospheric pressure term cancels out across the equality, provided consistency is maintained.


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