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Q10.9:
A U-tube contains water and methylated spirit separated by mercury. The mercury columns in the two arms are in level with 10.0 cm of water in one arm and 12.5 cm of spirit in the other. What is the specific gravity of spirit ?

Solution :

Step 1: Identifying the Principle of Hydrostatic Equilibrium

In a U-tube containing fluids in equilibrium, the pressure at any two points at the same horizontal level in a continuous fluid must be equal. Since the mercury columns in both arms are at the same level, the pressure exerted by the water column in the first arm must balance the pressure exerted by the methylated spirit column in the second arm at the interface with the mercury.

Step 2: Defining Physical Variables

Let the variables be defined as follows:

  • Height of water column ($h_w$) = $10.0 \text{ cm} = 0.10 \text{ m}$
  • Height of spirit column ($h_s$) = $12.5 \text{ cm} = 0.125 \text{ m}$
  • Density of water ($\rho_w$) = $1.0 \text{ g/cm}^3 = 1000 \text{ kg/m}^3$
  • Density of spirit ($\rho_s$) = Unknown
  • Acceleration due to gravity ($g$) = $9.8 \text{ m/s}^2$

Step 3: Formulating the Pressure Balance Equation

[Per the Hydrostatic Pressure Law $P = \rho gh$], at the level of the mercury interface:

$P_{\text{water}} = P_{\text{spirit}}$

$\rho_w \cdot g \cdot h_w = \rho_s \cdot g \cdot h_s$

Step 4: Algebraic Derivation for Density

Canceling the gravitational constant ($g$) from both sides of the equation:

$\rho_w \cdot h_w = \rho_s \cdot h_s$

$\rho_s = \rho_w \cdot \left( \frac{h_w}{h_s} \right)$

Step 5: Calculating Specific Gravity

Specific gravity (relative density) is defined as the ratio of the density of the substance to the density of water at standard temperature: $SG = \frac{\rho_s}{\rho_w}$.

Substituting the density ratio from Step 4:

$SG = \frac{h_w}{h_s}$

$SG = \frac{10.0 \text{ cm}}{12.5 \text{ cm}}$

$SG = 0.8$

Visual Representation of the Equilibrium

h_w h_s

Step 6: Final Tabulation of Data

Parameter Value
Height of Water ($h_w$) $10.0 \text{ cm}$
Height of Spirit ($h_s$) $12.5 \text{ cm}$
Calculated Specific Gravity 0.8

Final Solution: The specific gravity of the methylated spirit is 0.8.


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