In a double slit experiment using light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits.

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Noble Sharma

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PhD-Physics, with experience in teaching IIT JEE Physics and College level physics of various boards

Ans. spacing b/w the two slits (2d)= (Wavelegth/theta in radians)=0.34mm
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PhD-Physics, with experience in teaching IIT JEE Physics and College level physics of various boards

Fringe Width (w)=(lamda X D)/(slit seperation=2d) wher D is seperation b/w plane of slits and screen. therefore 2d=(lamda X D)/w. but for large values of D, angular width (theta in radians)= w/D. Hence finally 2d=lamda/(theta in radians). substituting the given values we get 2d=0.34 mm
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PhD-Physics, with experience in teaching IIT JEE Physics and College level physics of various boards

Spacing b/w two slits (2d)= (lamda)/(theta in radians), where theta is angular width in radians. So substituting the given values, 2d= 0.34 mm
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