A body of mass 5 kg is acted upon by two perpendicular forces of magnitude 8 N and 6 N. Find the magnitude and direction of the acceleration.

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Rishabh Jain

R= √ sqr8 + sqr (-6) =√ 64+36 = 10N
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The resultant force can be calculated by Parallelogram law of vectors. F = root of(8square+ 6square) = 10N From Newton's second law F = ma So acceleration a = F/m = 10/5 = 2 m/s2
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Resultant acceleration will be.2 m/square.
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Physics Tutor

Mag. Of acceleration=2 m/ sec square
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kindly find the answer
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Resultant force is 10N due to which acceleration get 2m/sq
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Net force Fsq=8sq+6sqB FSQ=100Nand henceF=10Na Accleration a=F/m=10/5=2meter/sec sq
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Resultant force by pythogoras theoram => √(8²+6²) =√(64+36) = √100 =10 N Magnitude of acceleration = F/m = 10 N / 5 Kg = 2 m/s² Direction of acceleration = tan inverse(6/8) = 36.9º inclined with the direction of the force of 8N
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Tutor

The resultaat force is 10N by triangle law of forces,and bt f=ma the accln is 10=5×a ,which gives a=2 m/sec^2
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Since two forces are acting in the direction perpendicular then resultant force=(8²+6²)½ F=10N F=m a 10=5 a a=2 m/s²
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Since two forces are acting in the direction perpendicular then resultant force=(8²+6²)½ F=10N F=m a 10=5 a a=2 m/s² read less
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