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Vivek Kumar Asthana

Gomtinagar, Lucknow, India - 226010

Vivek Kumar Asthana Class 11 Tuition trainer in Lucknow

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Vivek Kumar Asthana

Awarded as a Best Physics Teacher from IIT

Gomtinagar, Lucknow, India - 226010.

20 Students taught

5.0

UrbanPro Rating

Details verified of Vivek Kumar Asthana

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Overview

Ex-faculty in renowned ISC college of city. Presently working in government college as a physics lecturer. Result oriented and high personalized teaching with devotion. Courses in detail with complete range of syllabus. Provide short tricks to formulae & develop skills in students for the same
Strictly covers term wise exam syllabus. Conceptual clarity and individual problems are solved to the entire satisfaction of the student. Reasonable fee structure in easy installments

Languages Spoken

Hindi

English

Education

Lucknow university 2001

Master of Science (M.Sc.)

Csjm Kanpur 2004

Master of Education (M.Ed.)

Bhatkhande musical deemed University 2006

Visharad

Address

Gomtinagar, Lucknow, India - 226010

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Class 11 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

15

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Physics, Mathematics, Chemistry

Taught in School or College

Yes

Reviews (19)

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4.8 out of 5.0 19 reviews

Vivek Kumar Asthana https://s3-ap-southeast-1.amazonaws.com/tv-prod/member/photo/2947589-small.jpg Gomtinagar
4.80519
Vivek Kumar Asthana
H

"Best physics teacher in all of Lucknow. On top of being extremely knowledgeable he has the most friendly nature. I would absolutely recommend him. "

Vivek Kumar Asthana
H

"Sir is a great teacher. He explained me everything very clearly and was beyond helpful. He knew exactly what topics were important or not. He was always there to clear my doubts whenever I needed. He made all the numerical easier to understand and grasp. "

Vivek Kumar Asthana
A

"Vivek sir is adorable his physics is just on next level the way he explains is very nice. I am lucky to have a teacher like him I ws a very poor student in physics but when I met him my Mark's increased and I passed my inter with good Mark's in physics. "

Vivek Kumar Asthana
H

"Mr. Vivek Asthana is an exceptionally excellent teacher having vast knowledge of physics. He is very strategic so you need not to worry for your syllabus as it would be finished before the required period of time. He is a teacher who devotes a great amount of personal effort and interest in your daily classes. He explains the concepts in a very simple and understandable way also by performing small practicals during the classes. To conclude, I would just like to say that he is a teacher who can bring out a 'perfect score' from you and I would strongly recommend you to have him as your physics tuition teacher from my own personal experience. "

Have you attended any class with Vivek? Write a Review

FAQs

1. Which school boards of Class 12 do you teach for?

ISC/ICSE and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition, Class 12 Tuition, Engineering Entrance Coaching and NEET-UG Coaching Classes.

4. Do you provide a demo class?

No, I don't provide a demo class.

5. How many years of experience do you have?

I have been teaching for 15 years.

Answers by Vivek (9)

Answered on 27/04/2019 Tuition CBSE/Class 9/Mathematics

Hi, it depends on the individual whether he is happy with online tutoring or goes for personal. But one thing I can compare only in case of +1 or+2, i.e. online training can help to solve the problem but never helps to build your concepts.
Answers 607 Comments
Dislike Bookmark

Answered on 27/04/2019 Tuition

5 to 6 thousand for six days in a week for all three subjects
Answers 985 Comments
Dislike Bookmark

Answered on 21/10/2018 CBSE/Class 11/Science/Chemistry

When heated in air, the alkali metals form various oxides. Mention the oxides formed by Li, Na and K.

Li2O lithium oxide Na2O sodium oxide K2O pottasium oxide
Answers 1 Comments
Dislike Bookmark

Answered on 27/09/2018 CBSE/Class 11/Science/Physics

Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg ...more

Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so

mg-R=m a

R=m(g-a)

R=50(9.8-9)

R=50(0.8)

R=40 N

So the reading of weighing scale is =40/9.8

                                =4.08kg

Answers 4 Comments
Dislike Bookmark

Answered on 27/09/2018 CBSE/Class 11/Science/Physics

A block of mass m rests on a horizontal floor with which it has a coefficient of static friction u. It... ...more
A block of mass m rests on a horizontal floor with which it has a coefficient of static friction u. It is desired to make the body move by applying the minimum possible force F. Find the magnitude of F and the direction in which it has to be applied.

According to the Newton's law F-uR=Ma F=M(a+ug). {As R=Mg} In the direction of applied force
Answers 1 Comments
Dislike Bookmark
Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

15

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Physics, Mathematics, Chemistry

Taught in School or College

Yes

Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

15

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Physics, Mathematics, Chemistry

Taught in School or College

Yes

NEET-UG Coaching Classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in NEET-UG Coaching Classes

12

NEET Subjects

Physics, Chemistry

Engineering Entrance Coaching classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

12

Engineering Entrance Exams

GATE Coaching Classes, IIT JEE Coaching Classes, Delhi CEE Coaching Classes, BITSAT Coaching Classes

IITJEE Coaching

IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Advanced Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry , Physics

Answers by Vivek (9)

Answered on 27/04/2019 Tuition CBSE/Class 9/Mathematics

Hi, it depends on the individual whether he is happy with online tutoring or goes for personal. But one thing I can compare only in case of +1 or+2, i.e. online training can help to solve the problem but never helps to build your concepts.
Answers 607 Comments
Dislike Bookmark

Answered on 27/04/2019 Tuition

5 to 6 thousand for six days in a week for all three subjects
Answers 985 Comments
Dislike Bookmark

Answered on 21/10/2018 CBSE/Class 11/Science/Chemistry

When heated in air, the alkali metals form various oxides. Mention the oxides formed by Li, Na and K.

Li2O lithium oxide Na2O sodium oxide K2O pottasium oxide
Answers 1 Comments
Dislike Bookmark

Answered on 27/09/2018 CBSE/Class 11/Science/Physics

Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg ...more

Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so

mg-R=m a

R=m(g-a)

R=50(9.8-9)

R=50(0.8)

R=40 N

So the reading of weighing scale is =40/9.8

                                =4.08kg

Answers 4 Comments
Dislike Bookmark

Answered on 27/09/2018 CBSE/Class 11/Science/Physics

A block of mass m rests on a horizontal floor with which it has a coefficient of static friction u. It... ...more
A block of mass m rests on a horizontal floor with which it has a coefficient of static friction u. It is desired to make the body move by applying the minimum possible force F. Find the magnitude of F and the direction in which it has to be applied.

According to the Newton's law F-uR=Ma F=M(a+ug). {As R=Mg} In the direction of applied force
Answers 1 Comments
Dislike Bookmark

Contact

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Vivek Kumar Asthana describes himself as Awarded as a Best Physics Teacher from IIT. He conducts classes in Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching. Vivek is located in Gomtinagar, Lucknow. Vivek takes at students Home and Regular Classes- at his Home. He has 15 years of teaching experience . Vivek has completed Master of Science (M.Sc.) from Lucknow university in 2001 and Master of Education (M.Ed.) from Csjm Kanpur in 2004. HeĀ is well versed in Hindi and English. Vivek has got 19 reviews till now with 100% positive feedback.

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