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Given, the actual path length travelled is 23 km, displacement is 10 km and the time taken is 28 min.
(a)
Average speed of the taxi is given as,
v avg = Total Path length Time
Here, s is the total path length
Substitute the values in above equation.
v avg = Total Path length Time = 23 km ( 28 min )( 1 h 60 min ) =49.3 km/h
Hence, the average speed of the taxi is 49.3 km/h .
(b)
Magnitude of the average velocity is given as,
v avg = Displacement Time
Substitute the values in the above equation.
v avg = Displacement Time = 10 km ( 28 min )( 1 h 60 min ) =21.4 km/h
(c)
From the calculation in (a) and (b), it is obtained that the average speed is not equal to the magnitude of average velocity.
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Answered on 28 Apr Learn Chapter 4-Motion in a Plane
Deepika Agrawal
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Deepika Agrawal
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Answered on 28 Apr Learn Unit 4-Motion of System of Particles
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Answered on 28 Apr Learn Chapter 9-Mechanical Properties of Solids
Deepika Agrawal
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Mass of the big structure, M = 50,000 kg
Inner radius of the column, r = 30 cm = 0.3 m
Outer radius of the column, R = 60 cm = 0.6 m
Young’s modulus of steel, Y=2×1011Pa
Total force exerted, F=Mg=50000×9.8N
Stress = Force exerted on a single column =50000×9.84=122500N
Young’s modulus, Y=StressStrain
Strain =(F/A)Y
Where,
Area, A=π(R2−r2)=π((0.6)2−(0.3)2)
Strain =122500/[π((0.6)2−(0.3)2)×2×1011]=7.22×10−7
Hence, the compressional strain of each column is 7.22×10−7.
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Deepika Agrawal
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