UrbanPro

Take Class 11 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

The moment of inertia of a body about a given axis is 1.2kgm^2 . Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angular acceleration of 25rad/second ^2 must be applied about that axis for a duration of 

Asked by Last Modified  

12 Answers

Learn Physics

Follow 7
Answer

Please enter your answer

Physics online tutor with 1 year experience of teaching virtually.

Comments

C language Faculty (online Classes )

The correct option is B 2 sI=1.2 kgm2;t=?Krot=1500 Jα=25rad/s2ω=ω0+αtInitially the body was at rest, ωo=0Rotational kinetic energy, K=12Iω2⇒1500=12×1.2×w2w=√30001.2=50 rad/sω=ω0+αtωo=0t=wα=5025=2s
read more

The correct option is B 2 s
I=1.2 kgm2;t=?

Krot=1500 J

α=25rad/s2

ω=ω0+αt
Initially the body was at rest, ωo=0

Rotational kinetic energy, K=12Iω21500=12×1.2×w2

w=30001.2=50 rad/s

ω=ω0+αt
ωo=0
t=wα=5025=2s

read less
Comments

Msc physics student at a central university

t=1500/(1.2*625) This is straight from the formula and you get 2 seconds
Comments

Physics online tutor with 1 year experience of teaching virtually.

Comments

Hello you can call me i willl explain it
Comments

Maths and physics tutor since past years

Rotation kinetic energy= ½Iω² Where I = moment of Inertia ω = angular velocity And, kinematic relation for constant angular acceleration is ω(final) = ω(initial) + αt Where, α = angular acceleration t = time
read more

Rotation kinetic energy= ½Iω²

Where I = moment of Inertia

ω = angular velocity

And, kinematic relation for constant angular acceleration is

ω(final) = ω(initial) + αt

Where, α = angular acceleration

t = time

read less
Comments

Learn from the IITian with 6 yr of coaching experience

solution to above question
Comments

Answer : K= rotational kinetic energy ω = angular velocity I = moment of inertia
Comments

Teacher!

Comments

Physics and Maths - Grade XI and XII

To find the duration for which an angular acceleration must be applied to produce a certain rotational kinetic energy, we can use the following relationship between rotational kinetic energy (KE), moment of inertia (I), and angular velocity (ω): KE = \frac{1}{2} I \omega^2KE=21Iω2 Given...
read more

To find the duration for which an angular acceleration must be applied to produce a certain rotational kinetic energy, we can use the following relationship between rotational kinetic energy (KE), moment of inertia (I), and angular velocity (ω):

KE = \frac{1}{2} I \omega^2KE=21Iω2

Given that the rotational kinetic energy (KE) is 1500 J and the moment of inertia (I) is 1.2 kgm², we can solve for the angular velocity (ω):

1500 = \frac{1}{2} \times 1.2 \times \omega^21500=21×1.2×ω2

Solving for ω gives us:

\omega^2 = \frac{3000}{1.2}ω2=1.23000

\omega = \sqrt{\frac{3000}{1.2}}ω=1.23000

\omega \approx 50 \text{ rad/s}ω≈50 rad/s

Now, using the angular acceleration (α) of 25 rad/s², we can find the time (t) it takes to reach this angular velocity from rest using the equation:

\omega = \alpha tω=αt

Substituting the known values:

50 = 25t50=25t

t = \frac{50}{25}t=2550

t = 2 \text{ seconds}t=2 seconds

Therefore, an angular acceleration of 25 rad/s² must be applied about that axis for a duration of 2 seconds to produce a rotational kinetic energy of 1500 J.

read less
Comments

View 10 more Answers

Related Questions

Yes, I am available.I have 1 year experience in this field.You can contact me if you need me.
Balakrishnasingh
0 0
8
What is the unit of coefficient of friction?
The coefficient of friction is dimensionless (means it has no units) since it is a ratio of two similar quantities. Its purely a number
Mallikarjun
0 0
5
What is the fee for full year of PCM tuition?
500 FOR EACH SUBJECT PER MONTH(PHYSICS AND CHEMISTRY ONLY)
Mukesh
5 3
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

How To Solve A Mechanics Problem?
Solving a mechanics problem especially at JEE level is all about getting into right thinking framework. Step 1: Picking a frame of reference. It can be solved from inertial frame of reference or non-nertial...

How to Prepare for IIT JEE Physics
Hello Dear Students, In this article, we'll talk about a practical and achievable strategy to Score High Marks in IIT JEE PHYSICS.First of all, let me clear it; the number of books finished doesn't matter...
A

Abhay

0 0
0

Nuclear Structure
An atom consists of an extremely small, positively charged nucleus surrounded by a cloud of negatively charged electrons. Although typically the nucleus is less than one ten-thousandth the size of the...

How to Solve Numericals in Physics?
Are you scared of numerical? Do you think you don't understand them? If yes, then read ahead. See, it might be any exam, but numerical won't leave your back. So let's talk about common problems and their...

Law of conservation of angular momentum.
It states that if net torque acting on an isolated system is zero, the angular momentum remains conserved. Since Torque is equal to the rate of change of angular momentum so when torque is zero, dL/dt=0 So,...

Recommended Articles

Once over with the tenth board exams, a heavy percentage of students remain confused between the three academic streams they have to choose from - science, arts or commerce. Some are confident enough to take a call on this much in advance. But there is no worry if as a student you take time to make choice between - science,...

Read full article >

Quality education does not only help children to get a successful career and life, but it also hugely contributes to society. The formal education of every child starts from school. Although there are numerous schools, parents find it challenging to choose the right one that would fit their child. It is difficult for them...

Read full article >

E-learning is not just about delivering lessons online. It has a much broader scope that goes beyond manual paper or PowerPoint Presentations. To understand the reach of E-learning and how the whole process works in developing the Educational system, we will discuss a few points here. Let us find out how this new learning...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 11 Tuition Classes?

The best tutors for Class 11 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 11 Tuition with the Best Tutors

The best Tutors for Class 11 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more