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# The moment of inertia of a body about a given axis is 1.2kgm^2 . Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angular acceleration of 25rad/second ^2 must be applied about that axis for a duration of

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The correct option is B 2 sI=1.2 kgm2;t=?Krot=1500 Jα=25rad/s2ω=ω0+αtInitially the body was at rest, ωo=0Rotational kinetic energy, K=12Iω2⇒1500=12×1.2×w2w=√30001.2=50 rad/sω=ω0+αtωo=0t=wα=5025=2s

The correct option is B 2 s
I=1.2 kgm2;t=?

Krot=1500 J

ω=ω0+αt
Initially the body was at rest, ωo=0

Rotational kinetic energy, K=12Iω21500=12×1.2×w2

ω=ω0+αt
ωo=0
t=wα=5025=2s

Moment of inertia of the body depends upon the mass of the body, axis of rotation of the body and shape and size of the body.

Msc physics student at a central university

t=1500/(1.2*625) This is straight from the formula and you get 2 seconds

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