The Earth moving round the Sun in a circular orbit is acted upon by a force, and hence work must be done on the Earth by this force. Do you agree with this statement?

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Soumodeep Mitra

Current researcher in Gravity, wants to teach about the frontiers of physics

The force on earth jn circular trajectory is gravity,acting radially inward...the direction of motion is tangential.....as u knw work is dot product of force and dx, the work done is zero.
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Force and direction of motion both are perpendicular to each other so displacement is pependicular to force work will be zero.
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Yes indeed, work is done on earth by this force. However, if you consider the trajectory to be circular, it's zero as the dispalcemediis tangential to the force acted upon. While, the realisitic motion is elliptical, the work is indeed done on the earth by the sun.
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Not Circular Orbit,earth rounds the sun in a Elliptical Orbit,and is acted upon by a Centrifugal force .Thank you
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earth moves around the sun in elliptical orbit and centripetal force is the cause of this motion.
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The force involved is gravitational which is a conservative force and as this is a motion in a closed loop it doesn't perform any work
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Prof.G Ramakrishna

in the sense of physics no work has done.in this case force acting on earth and tangential displacement are perpendicular.in the following cases no work is done,1.when applied force and displacement are orthogonal ( perpendicular).2.net applied force is zero.3no displacement after the application of...
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in the sense of physics no work has done.in this case force acting on earth and tangential displacement are perpendicular.in the following cases no work is done,1.when applied force and displacement are orthogonal ( perpendicular).2.net applied force is zero.3no displacement after the application of the force. read less
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Work Done= ∫F.ds = ∫F.s.cosθ= ∫F.s.cos90º = Zero as Movement of earth is perpendicular to the Gravitational Force applied on earth by the Sun, hence force is perpendicular to the displacement. So work done is Zero. Hence, I do not agree to your statement.
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Work Done=∫F.ds =∫F.s.cosθ=∫F.s.cos90º = Zero as Movement of earth is perpendicular to theGravitational Force applied on earth by the Sun, hence force is perpendicular to the displacement. So work done is Zero. Hence, I do not agree to your statement. read less
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The force on earth jn circular trajectory is gravity,acting radially inward...the direction of motion is tangential.....as u knw work is dot product of force and dx, the work done is zero.
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