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C Language Classes > C Language in Hyderabad > Sadiq

Sadiq C Language trainer in Hyderabad

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Sadiq

C language Faculty (online Classes )

Basheer Bagh Chandra Nagar, Hyderabad, India - 500029.

11 reviews

13 Students

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Education

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Overview

I am a teacher and engineer having experience in programming languages. Holding a master's degree in embedded systems. Worked as project coordinator in btech final year students for academic projects.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Address

Basheer Bagh Chandra Nagar, Hyderabad, India - 500029

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Teaches

C Language Classes
11 reviews
4 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in C Language Classes

10

Documents (1)

Introduction

Reviews (11)

4.9 out of 5 11 reviews

Sadiq https://p.urbanpro.com/tv-prod/member/photo/11332792-small.jpg Basheer Bagh Chandra Nagar
4.90511
Sadiq
V

C Language

"Sir has teaching excellent. I am lucky to find like sadiq sir. He is clearing doubts my experince is very good sir taught me c language well. My rating is 4.8 out of 5. "

Sadiq
V

C Language

"Sadiq sir has clearly taught C programming language from basics and fees which was asked is extremely less with high quality,surely his classes would help students to improve the coding abilities of any learners,He also agreed for conducting mock interview and mock test.Thanks sir for teaching C programming to me. "

Sadiq
G
Verified Student

C Language

"This class was excellent this instructor was very knowledgeable with excellent presentation skills superb. "

Sadiq
M

C Language

"It teach very well and I can understand everything. I am going to offline class I loved his explanation and I have gain some knowledge. "

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Have you attended any class with Sadiq?

FAQs

1. Which classes do you teach?

I teach C Language Class.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 10 years.

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Answers by Sadiq (2533)

Answered 14 hrs ago

An LLB (Bachelor of Laws) program typically lasts 3 to 4 years and includes core subjects like Contract Law, Criminal Law, Constitutional Law, Tort Law, Property Law, Administrative Law, Jurisprudence, International Law, and Legal Research and Writing
Answers 3 Comments
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Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

The circumference of the circle = 31.4 cm⇒ 2π r = 31.4⇒ 2 x 3.14 x r = 31.4⇒r =31.4/2 x 3.14 = 5 cmThen area of the circle = π r 2= 3.14 x 5 x 5= 78.5 cm2Therefore the radius and the area of the circle are 5 cm and 78.5 cm2 respectively.
Answers 3 Comments
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Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Radius of circular sheet (r₁) = 4 cm Radius of removed circle (r₂) = 3 cm Area of remaining sheet = Area of circular sheet -- Area of removed circle = πr₁2 - πr₂2 = π (r₁2 - r₂2) = 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2 Thus, the area of the remaining... ...more
Radius of circular sheet (r₁) = 4 cm Radius of removed circle (r₂) = 3 cm Area of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2 = π (r₁2 - r₂2) = 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2 Thus, the area of the remaining sheet is 21.98
Answers 2 Comments
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Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Radius of the circular clock (r) = 15 cm Circumference of the circular clock = 2πr = 2 × 3.14 × 15 cm = 94.2 cm Therefore, the tip of the minute hand moves 94.2 cm in 1 hour.
Answers 2 Comments
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Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Area of the circular flower garden = 314 m2 Radius of the circular portion covered by the sprinkler = 12 m Area covered by the sprinkler = πr2 = 3.14 × 12 m × 12 m = 452.16 m2 The area covered by the sprinkler is greater than the area of the entire garden. So, we can say that. "Yes,... ...more
Area of the circular flower garden = 314 m2 Radius of the circular portion covered by the sprinkler = 12 m Area covered by the sprinkler = πr2 = 3.14 × 12 m × 12 m = 452.16 m2 The area covered by the sprinkler is greater than the area of the entire garden. So, we can say that. "Yes, the sprinkler will water the entire garden."
Answers 2 Comments
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Teaches

C Language Classes
11 reviews
4 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in C Language Classes

10

Answers by Sadiq (2533)

Answered 14 hrs ago

An LLB (Bachelor of Laws) program typically lasts 3 to 4 years and includes core subjects like Contract Law, Criminal Law, Constitutional Law, Tort Law, Property Law, Administrative Law, Jurisprudence, International Law, and Legal Research and Writing
Answers 3 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

The circumference of the circle = 31.4 cm⇒ 2π r = 31.4⇒ 2 x 3.14 x r = 31.4⇒r =31.4/2 x 3.14 = 5 cmThen area of the circle = π r 2= 3.14 x 5 x 5= 78.5 cm2Therefore the radius and the area of the circle are 5 cm and 78.5 cm2 respectively.
Answers 3 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Radius of circular sheet (r₁) = 4 cm Radius of removed circle (r₂) = 3 cm Area of remaining sheet = Area of circular sheet -- Area of removed circle = πr₁2 - πr₂2 = π (r₁2 - r₂2) = 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2 Thus, the area of the remaining... ...more
Radius of circular sheet (r₁) = 4 cm Radius of removed circle (r₂) = 3 cm Area of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2 = π (r₁2 - r₂2) = 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2 Thus, the area of the remaining sheet is 21.98
Answers 2 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Radius of the circular clock (r) = 15 cm Circumference of the circular clock = 2πr = 2 × 3.14 × 15 cm = 94.2 cm Therefore, the tip of the minute hand moves 94.2 cm in 1 hour.
Answers 2 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 9/Class 9 Mathematics/Chapter 3 Coordinate Geometry/EXERCISE - 9.2

...more

Area of the circular flower garden = 314 m2 Radius of the circular portion covered by the sprinkler = 12 m Area covered by the sprinkler = πr2 = 3.14 × 12 m × 12 m = 452.16 m2 The area covered by the sprinkler is greater than the area of the entire garden. So, we can say that. "Yes,... ...more
Area of the circular flower garden = 314 m2 Radius of the circular portion covered by the sprinkler = 12 m Area covered by the sprinkler = πr2 = 3.14 × 12 m × 12 m = 452.16 m2 The area covered by the sprinkler is greater than the area of the entire garden. So, we can say that. "Yes, the sprinkler will water the entire garden."
Answers 2 Comments
Dislike Bookmark

Book a Demo

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Sadiq describes himself as C language Faculty (online Classes ). He conducts classes in C Language. Sadiq is located in Basheer Bagh Chandra Nagar, Hyderabad. Sadiq takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 10 years of teaching experience . He is well versed in English and Hindi. Sadiq has got 11 reviews till now with 100% positive feedback.

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