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Q8.6 (b):
Draw formulas for the first five members of each homologous series beginning with the following compounds. (b) $CH_3COCH_3$

Solution :

1. Identification of Homologous Series

The given compound is $CH_3COCH_3$ (Propan-2-one). This molecule contains a carbonyl group ($>C=O$) bonded to two alkyl groups. The general formula for this homologous series (Ketones) is $C_nH_{2n}O$.

2. Determining the Homologous Series Sequence

Ketones require a minimum of three carbon atoms to place the carbonyl group between two alkyl substituents. The series proceeds by the successive addition of a methylene ($-CH_2-$) group.

3. Structural Formulas of the First Five Members

Member IUPAC Name Condensed Formula
1 Propan-2-one $CH_3COCH_3$
2 Butan-2-one $CH_3COCH_2CH_3$
3 Pentan-2-one $CH_3COCH_2CH_2CH_3$
4 Hexan-2-one $CH_3COCH_2CH_2CH_2CH_3$
5 Heptan-2-one $CH_3COCH_2CH_2CH_2CH_2CH_3$

4. Structural Representation of Propan-2-one

CH₃ C=O CH₃ Structural representation of the base member: Propan-2-one

5. Theoretical Justification

By the definition of a homologous series [IUPAC Gold Book criteria]:

  • Each member differs from the next by a constant $-CH_2-$ unit.
  • All members share the same functional group ($>C=O$).
  • Chemical properties remain similar across the series, while physical properties (boiling point, solubility) change gradually as the carbon chain length increases.

Final Solution: The first five members are Propan-2-one ($CH_3COCH_3$), Butan-2-one ($CH_3COCH_2CH_3$), Pentan-2-one ($CH_3CO(CH_2)_2CH_3$), Hexan-2-one ($CH_3CO(CH_2)_3CH_3$), and Heptan-2-one ($CH_3CO(CH_2)_4CH_3$).


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