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Q8.15:

What is the relationship between the members of following pairs of structures ? Are they structural or geometrical isomers or resonance contributors ?

(b) 

Solution :

Step 1: Structural Analysis of the Structures

To determine the relationship between the two structures, we first define the molecular formula and connectivity of each molecule provided in the image.

  • Structure 1 (Left): The structure represents 2-methylbut-2-ene. The carbon backbone is a 4-carbon chain (but-2-ene) with a methyl group ($CH_3$) attached to the second carbon.
  • Structure 2 (Right): The structure represents 2-methylbut-2-ene. It is essentially the same molecule, simply drawn in a different spatial orientation (a rotation about the $C=C$ double bond or a flip).

Step 2: Assessing Isomerism

We evaluate the criteria for different types of isomers:

  • Structural Isomers: These require different connectivity of atoms (different IUPAC names). Both structures here possess the same connectivity ($2\text{-methylbut-2-ene}$). Thus, they are not structural isomers.
  • Geometrical Isomers ($cis/trans$ or $E/Z$): Geometrical isomerism occurs when there is restricted rotation around a double bond and different groups are attached to the carbons involved in the double bond.
    In $2\text{-methylbut-2-ene}$, one of the double-bonded carbons (specifically $C_2$) is bonded to two identical methyl groups ($CH_3$).
    [Per the Cahn-Ingold-Prelog (CIP) priority rules, a molecule cannot exhibit geometrical isomerism if one of the double-bonded carbons is attached to two identical groups.]
  • Resonance Contributors: Resonance contributors must have identical atomic positions and differ only in the distribution of $\pi$ electrons or lone pairs. Since the sigma-bond framework is identical and the $\pi$ bond location is identical, these are not resonance structures but rather the same molecule.

Step 3: Identification of Relationship

Since the structures possess the same chemical formula, the same IUPAC name, and the same connectivity, and the molecule is incapable of existing as geometrical isomers, the two structures are identical representations of the same molecule.

Structure 1 $CH_3$ $CH_3$ ≡ Structure 2 $CH_3$ $CH_3$

Final Solution: The members of the pair are identical structures. They are not isomers of any kind, nor are they resonance contributors; they represent the same molecule (2-methylbut-2-ene) viewed in different orientations.


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