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Q8.4:

Give the IUPAC names of the following compounds : (d) 

Solution :

Step 1: Identifying the Principal Functional Group

The provided image displays a chemical structure containing a carbon chain with a ketone functional group ($\text{C=O}$). According to IUPAC nomenclature rules, the ketone group receives the priority suffix "-one". The carbon atom of the carbonyl group must be assigned the lowest possible locant during the numbering of the parent chain.

Step 2: Determining the Parent Carbon Chain

Counting the carbons in the continuous chain containing the carbonyl group:

  • The chain consists of 5 carbon atoms.
  • A 5-carbon alkane chain is named "pentane".
  • With the ketone functional group, the parent name becomes "pentanone".
[Per IUPAC Blue Book P-64.2.1: The principal chain is the longest carbon chain containing the principal functional group.]

Step 3: Numbering the Chain

To ensure the carbonyl carbon has the lowest number, we number from left to right:

  • $C_1$: Terminal methyl group ($\text{CH}_3$)
  • $C_2$: Carbonyl group ($\text{C=O}$)
  • $C_3$: Methylene group ($\text{CH}_2$)
  • $C_4$: Methylene group ($\text{CH}_2$)
  • $C_5$: Terminal methyl group ($\text{CH}_3$)
The ketone group is at position $2$.

Step 4: Constructing the IUPAC Name

Combining the parent chain length and the locant of the functional group:

  • The parent name is "pentan-2-one".
[Per IUPAC Rule P-14.4: Locants are placed immediately before the part of the name to which they relate.]

Visual Representation

CH3 C(=O) CH2 CH2 CH3 Structure: Pentan-2-one

Final Solution: Pentan-2-one


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