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Q8.37:
In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

Solution :

Step 1: Chemical Basis of Lassaigne’s Test

The Lassaigne’s test (or sodium fusion test) is utilized to detect the presence of nitrogen, sulfur, and halogens in organic compounds. In the case of nitrogen-containing organic compounds, the fusion of the substance with metallic sodium converts covalently bonded nitrogen into ionic sodium cyanide ($NaCN$).

The chemical reaction is represented as: $Na + C + N \xrightarrow{\Delta} NaCN$ [Ref: Chemical fusion principle]

Step 2: Conversion to Ferrous Cyanide

The resulting $NaCN$ extract is treated with freshly prepared ferrous sulfate ($FeSO_4$). This reacts to form sodium ferrocyanide, chemically known as sodium hexacyanoferrate(II).

The reaction is: $FeSO_4 + 6NaCN \rightarrow Na_4[Fe(CN)_6] + Na_2SO_4$ [Ref: Ligand substitution in coordination chemistry]

Step 3: Formation of Ferri-Ferrocyanide (Prussian Blue)

Upon addition of a small amount of dilute sulfuric acid or hydrochloric acid, some $FeSO_4$ is oxidized to $Fe^{3+}$ ions (ferric ions) by the atmosphere or the acidic medium. These ferric ions react with the sodium ferrocyanide to form the complex iron(III) hexacyanoferrate(II).

The balanced stoichiometric equation is: $3Na_4[Fe(CN)_6] + 4Fe^{3+} \rightarrow Fe_4[Fe(CN)_6]_3 \cdot xH_2O$ [Ref: Coordination complex precipitation]

Step 4: Molecular Structure Analysis

The deep blue precipitate, known as Prussian blue, is mathematically and chemically defined as ferric ferrocyanide. The coordination entity consists of an octahedral $[Fe(CN)_6]^{4-}$ core coordinating with $Fe^{3+}$ cations.

Prussian Blue Formation Process: $Fe^{3+}$ + $[Fe(CN)_6]^{4-}$ $\rightarrow$ $Fe_4[Fe(CN)_6]_3$ (Prussian Blue)

Step 5: Tabular Summary of Reagents

Reagent Role
Metallic Sodium Converts organic nitrogen to $NaCN$
Ferrous Sulfate ($FeSO_4$) Provides $Fe^{2+}$ for ferrocyanide formation
Acidic Medium ($H_2SO_4/HCl$) Facilitates $Fe^{2+} \rightarrow Fe^{3+}$ oxidation

Final Solution: In the Lassaigne’s test, the Prussian blue colour is obtained due to the formation of Ferric ferrocyanide, chemically represented as $Fe_4[Fe(CN)_6]_3$.


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