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Q8.31:
Why is it necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test?

Solution :

Initial Theoretical Framework

The detection of sulfur in an organic compound via the sodium fusion extract (Lassaigne's test) involves the conversion of organic sulfur into sodium sulfide ($Na_2S$). To test for the presence of sulfide ions ($S^{2-}$), lead acetate solution is added to the sodium extract.

The chemical reaction for the detection of sulfur is:

$Na_2S + (CH_3COO)_2Pb \rightarrow PbS_{(s)} + 2CH_3COONa$

This reaction forms a black precipitate of lead sulfide ($PbS$), which confirms the presence of sulfur [Per the principles of qualitative inorganic analysis].

Step 1: Role of Acidification in the Test

Sodium fusion extract is typically alkaline due to the presence of unreacted sodium metal or excess sodium hydroxide produced during the fusion process. Acidification is required to ensure that any potential interfering species are neutralized and that the solution is slightly acidic to facilitate the precipitation reaction without causing secondary side reactions [By the Law of Mass Action and solubility product principles].

Step 2: Analysis of Sulfuric Acid ($H_2SO_4$) Usage

If sulfuric acid ($H_2SO_4$) were used for acidification, the following chemical interference would occur:

$H_2SO_4 + (CH_3COO)_2Pb \rightarrow PbSO_{4(s)} + 2CH_3COOH$

Consequences of using $H_2SO_4$:

  • Precipitation interference: Lead(II) sulfate ($PbSO_4$) is a white, insoluble precipitate. Its formation would obscure the observation of the black lead sulfide ($PbS$) precipitate, leading to a false negative or ambiguous result.
  • Sulfate contamination: If the organic compound contained sulfate groups, adding $H_2SO_4$ would further complicate the analysis by shifting the solubility equilibria.

Step 3: Analysis of Acetic Acid ($CH_3COOH$) Usage

Acetic acid is a weak acid. Its utilization provides two distinct advantages:

  • Compatibility: Lead(II) acetate is the reagent of choice because lead(II) ethanoate is soluble in water. Adding acetic acid suppresses the ionization of the acetate ions, maintaining a stable medium.
  • Lack of Interfering Anions: Unlike sulfate ions ($SO_4^{2-}$), acetate ions ($CH_3COO^-$) do not form an insoluble precipitate with lead ions ($Pb^{2+}$). Thus, the black precipitate of $PbS$ is formed without any competing white precipitate contamination [Per the Common Ion Effect and Selective Precipitation criteria].

Comparison Table of Acidifying Agents

Acidifying Agent Product with Lead Reagent Resulting Observation
Sulfuric Acid ($H_2SO_4$) $PbSO_4$ (White ppt) Interferes with black $PbS$ visibility
Acetic Acid ($CH_3COOH$) $Pb(CH_3COO)_2$ (Soluble) Clear observation of black $PbS$

Geometric Representation of the Precipitation Conflict

Sulfuric Acid Addition PbSO₄ (White) masks PbS Acetic Acid Addition PbS (Black) clearly visible

Final Solution: Acetic acid is used because it does not form an insoluble precipitate with lead ions, whereas sulfuric acid would form white lead(II) sulfate ($PbSO_4$), which interferes with the identification of the black lead(II) sulfide ($PbS$) precipitate.


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